我有一个sql查询：

SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as availability 
  FROM ( 
        SELECT count(roomTypeDay2.room_type_id) as _days  
          FROM room_type_day as roomTypeDay2 
     LEFT JOIN room_type as roomType2 on roomTypeDay2.room_type_id = roomType2.id  
         WHERE roomType2.accommodation_id=3 
           AND roomTypeDay2.date IN ( '2018-06-09 00:00:00','2018-06-10 00:00:00','2018-06-11 00:00:00')  
      GROUP BY roomTypeDay2.room_type_id  
        HAVING COUNT(roomTypeDay2.room_type_id) = 3 
       ) as disponible

这很好，但是现在，我想过滤第一个日期行（2018-06-09 00:00:00）是否
“最短住宿时间<=3天，最长释放时间<=2天”
参数，但我不知道怎么做。
我尝试将以下行添加到查询：
和（roomtypeday2.date='2018-06-09 00:00:00'和roomtypeday2.min\u night\u stay<=3和roomtypeday2.release\u days<=2）
但这不是正确的查询。
乳突

SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as availability 
   FROM ( 
        SELECT count(roomTypeDay2.room_type_id) as _days  
          FROM room_type_day as roomTypeDay2 
     LEFT JOIN room_type as roomType2 on roomTypeDay2.room_type_id = roomType2.id  
           AND roomType2.accommodation_id=3 
         WHERE roomTypeDay2.date IN ( '2018-06-09 00:00:00','2018-06-10 00:00:00','2018-06-11 00:00:00')  
      GROUP BY roomTypeDay2.room_type_id  
        HAVING COUNT(roomTypeDay2.room_type_id) = 3 
         ) as disponible

解决方案

SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as availability 
    FROM ( 
        SELECT count(roomTypeDay2.room_type_id) as _days  
        FROM room_type_day as roomTypeDay2  
        LEFT JOIN room_type as roomType2 on roomTypeDay2.room_type_id = roomType2.id 
        WHERE roomType2.accommodation_id=3 
        AND roomTypeDay2.num_rooms_available > 0  
        AND (roomTypeDay2.date = '2018-06-12 00:00:00' AND roomTypeDay2.min_night_stay <= 2 AND roomTypeDay2.release_days <= 2 )
        OR roomTypeDay2.date IN ( '2018-06-13 00:00:00','2018-06-14 00:00:00')  
        GROUP BY roomTypeDay2.room_type_id  
        HAVING COUNT(roomTypeDay2.room_type_id) = 3 
    ) as disponible