我正在使用node和express以及mysql作为数据库。我创建了一个ejs文件,其中有一个表单(method=post)
在我的服务器文件中,我可以检索该表单发送的数据,甚至可以将其记录到console.log中并获得所需的输出。因为表单中有多个条目,所以我使用不同的变量将这些条目存储在我的服务器文件中。
在查询中,当我传递那些要插入到数据库中的变量时,数据库只插入null,而不是存储在变量中的实际数据。
表格代码如下:
<form action="/newuser" style="border:1px solid #ccc" method="post">
<div class="container">
<h1>Sign Up</h1>
<p>Please fill in this form to create an account.</p>
<hr>
<label for="Name"><b>Name</b></label>
<input type="text" placeholder="Enter Name" name="name" required>
<label for="email"><b>Email</b></label>
<input type="text" placeholder="Enter Email" name="email" required>
<label for="psw"><b>Password</b></label>
<input type="password" placeholder="Enter Password" name="psw" required>
<hr>
<label for="address"><b>Address</b></label>
<input type="text" placeholder="House no and Street" name="address" required>
<label for="city"><b>City</b></label>
<input type="text" placeholder="Enter City" name="city" required>
<label for="pin"><b>Postal Code</b></label>
<input type="number" placeholder="Enter pin" name="pin" required>
<label for="country"><b>Country</b></label>
<input type="text" placeholder="Enter Country" name="country" required>
<label for="mobile"><b>Mobile Number</b></label>
<input type="number" placeholder="Enter Mobile Number" name="mobile" required>
<div class="clearfix">
<a href="/"><button type="button" class="cancelbtn">Cancel</button></a>
<button type="submit" class="signupbtn">Sign Up</button>
</div>
</div>
</form>
服务器文件上的代码如下所示:
var express = require("express");
var bodyParser = require("body-parser");
var app = express();
var mysql = require('mysql');
app.use( express.static( "public" ) );
app.use( bodyParser.json() ); // to support JSON-encoded bodies
app.use(bodyParser.urlencoded({ // to support URL-encoded bodies
extended: true
}));
var connection = mysql.createConnection({
host: "localhost",
user:"root",
password:"",
database:"bakery"
});
//some more code to get different routes
connection.connect(function(error){
if(error){
console.log("Error while connecting to database")
}
else{
// console.log("connected");
connection.query("SELECT * FROM products", function (err, result, fields) {
if (err) throw err;
for (var i = 0; i < result.length; i++) {
var row = result[i];
console.log(row.ProductName, "costs", row.Price, "and its from category", row.Category );
}
// console.log(result);
})
}});
app.use(bodyParser.urlencoded({ extended: true }));
app.set("view engine", "ejs");
app.post("/newuser", function(req, res) {
// get data from forms and add to the table called user..
var name = req.body.name;
var email = req.body.email;
var password = req.body.psw;
var city = req.body.city;
var address = req.body.address;
var country= req.body.country
var pin = req.body.pin;
var mobile = req.body.mobile;
console.log(name, mobile, pin);
connection.query("INSERT INTO user (Name, Email, Address, City, Country, password) VALUES", (name , email, address, city, country , password), function (err, result) {
if (err) throw err;
console.log("1 record inserted");
});
res.redirect("/");
使用此代码,无论我在表单中键入什么,它都只向数据库中插入null。
2条答案
按热度按时间s3fp2yjn1#
试着这样做:
ev7lccsx2#
我认为问题在于你的查询语法。我把你的代码重组为下面的代码。我希望它能解决这个问题。