我想更新一下 status
通过按“批准/拒绝”按钮在“我的叶”表上。以下是我的表架构:
到目前为止,我已经做到了:
<?php
if(isset($_POST['approved']))
{
echo "Approved";
$status=$_POST['approved'];
}
if(isset($_POST['rejected']))
{
echo "Rejected";
$status=$_POST['rejected'];
}
?>
<!-- Begin page content -->
<div class="container">
<div class="page-header">
<h3>Employee Leaves</h3>
<div class="table-responsive">
<table class="table">
<tr>
<th>Employee Name</th>
<th>Phone</th>
<th>Email</th>
<th>From</th>
<th>To</th>
<th>Reason</th>
<th>Status</th>
<th>---</th>
</tr>
<?php
include ('database.php');
$result = $database->prepare ("SELECT * FROM leaves order by id DESC");
$result ->execute();
for ($count=0; $row_message = $result ->fetch(); $count++){
?>
<tr>
<td><?php echo $row_message['full_name']; ?></td>
<td><?php echo $row_message['phone']; ?></td>
<td><?php echo $row_message['email']; ?></td>
<td><?php echo $row_message['fromdate']; ?></td>
<td><?php echo $row_message['todate']; ?></td>
<td><?php echo $row_message['reason']; ?></td>
<td><?php echo $row_message['status']; ?></td>
<td>
<form method="post" action="update.php">
<input type="hidden" value="<?php echo $row_message['id']; ?>" />
<input type="submit" value="Approved" name="approved"></input>
<input type="submit" value="Rejected" name="rejected"></input>
</form>
</td>
</tr>
<?php } ?>
</table>
<a href="home"><button type="button" class="btn btn-primary"><i class="glyphicon glyphicon-arrow-left"></i> Back</button></a>
</div>
</div>
</div>
</div>
</div>
这是我的update.php
<?php
$con = mysqli_connect('localhost', 'root', '');
mysqli_select_db($con, 'leaves');
$sql = "UPDATE leaves SET status = :status WHERE id = :id";
if(mysqli_query($con, $sql))
header("refresh:1; url=view-leave.php");
else
echo "Error";
?>
当我点击approve/reject时,我得到了“error”。我想问题出在 update.php
. 我不知道是什么,也不知道在哪里。
3条答案
按热度按时间5jvtdoz21#
必须在此处写入数据库名称:
9jyewag02#
您是否尝试为
$msg='';
以及$status = '';
?zpjtge223#
试试这个:
update.php
```