正如标题所说。我存储的从php到ajax再到另一个php的变量不能用在sql中的“select”语句中，只能用在“insert”上。我试着在sql的“insert”语句中使用变量“$\u post[”tweet“]”，它可以工作。在此处输入图像描述，但在select语句中它不起作用。我甚至不能在来自ajax的变量中使用echo。
chatproftouser.php
<?php
include 'header.php';
include 'connect.php';
session_start();
if(isset($_GET['UID'])){
$userid = $_GET['UID'];
$query = mysqli_query($conn,"SELECT * FROM usertable WHERE userid LIKE '$userid'") or die(mysql_error());
if(mysqli_num_rows($query)>0)
{
while ($a = mysqli_fetch_array($query))
{
$userid = $a['userid'];
$username = $a['username'];
$useremail = $a['useremail'];
?>
<html>
<body>
<div id=sendername>
<p><?php echo $username ?></p>
<p><?php echo $useremail ?></p>
</div>
<div class="container box">
<form name="sendmessage" method="post">
<div class="form-group">
<textarea name="usermessage" id="usermessage" class="form-control" rows="3"></textarea>
</div>
<div class="form-group" align="right">
<input type="button" name="sendusermessagebutton" id="sendusermessagebutton" value="Send" class="btn btn-info" />
</div>
</form>
</div>
<div id=chatprof>
<!-- HERE IS THE CHATLOG -->
</div>
<script>
$(document).ready(function(){
var tweet_txt = "<?php echo $useremail?>";
$.ajax
({
url:"chatprof.php",
method:"POST",
data:{tweet:tweet_txt},
dataType:"text",
});
});
</script>
<script>
$(document).ready(function(){
setInterval( function(){ $('#chatprof').load('chatprof.php'); }, 2000 );
});
</script>
<script type="text/javascript" src="js/insertusermessage.js"></script>
</body>
</html>
<?php
}
}else{
echo "Theres is no ID like that";
header("Location:chatprofmessenger.php");
}
}
?>这是我的另一个php for select语句。
chatprof.php软件
<?php
session_start();
include 'connect.php';
if(isset($_POST["tweet"]))
{
$prfemail = $_SESSION['prfemail'];
$tweet = mysqli_real_escape_string($conn, $_POST["tweet"]);
$sql = mysqli_query($conn,"SELECT * FROM chatlogs WHERE useremail='".$tweet."' AND prfemail='$prfemail'");
if(mysqli_num_rows($sql) > 0)
{
while($a = mysqli_fetch_array($sql))
{
$useremail = $a['useremail'];
$message = $a['message'];
echo $useremail;
echo "<br>";
echo $message;
}
}
}
?>先谢谢你。
暂无答案！
目前还没有任何答案，快来回答吧！