facebook api-保存配置文件图像

ljo96ir5  于 2021-06-23  发布在  Mysql
关注(0)|答案(0)|浏览(217)

试图从facebook api中保护个人资料img。这段代码将得到url/downloadlink,但现在我想把它保存在服务器上的某个地方,这样我就可以把它从数据库中取出并显示在某个地方。我想我可能需要 php copy 但我不确定。我也已经在google上搜索过了,但那是facebook api的旧版本。

$oAuth2Client = $FB->getOAuth2Client();
if (!$accessToken->isLongLived())
    $accessToken = $oAuth2Client->getLongLivedAccessToken($accessToken);

$response = $FB->get("/me?fields=id, first_name, last_name, email,gender,link, birthday,picture.type(large)", $accessToken);
$userData = $response->getDecodedBody();

$fb_foto_url = $userData['picture']['data']['url']; 

$voornaam= $app->get_klant_fb($userData['first_name']);
$_SESSION['voornaam'] = $userData['first_name'];
$_SESSION['achternaam'] = $userData['last_name'];

$fb_fotoUrl = $app->saving_fb_foto($userData['picture']['data']['url']);

//data ophalen
$klant= $app->get_klant_fb($userData['id']);
if($klant['id'] > 0) {
    //sessie klant zetten
    $_SESSION['klant_id'] = $klant['id'];
} else {
    //klant aanmaken
    unset($query);
    $query['oauth_uid']     = $userData['id'];
    $query['ledenpagina_id']= $_SESSION['ledenpagina_id'];
    $query['voornaam']      = $userData['first_name'];
    $query['achternaam']    = $userData['last_name'];
    $query['emailadres']    = $userData['email'];
    $query['geboortedatum'] = $userData['birthday'];
    $query['gender']        = $userData['gender']; 
    $query['link']          = $userData['link'];
    $query['foto']          = $userData['picture']['data']['url'];

    $app->insert_query('klanten', $query);

    $klant= $app->get_klant_fb($userData['id']);
    if($klant['id'] > 0) {
        $_SESSION['klant_id'] = $klant['id'];  
    }
}

暂无答案!

目前还没有任何答案,快来回答吧!

相关问题