我有一个mysql函数，有两个参数，即user\u id和post\u id
我的职责是：

CREATE FUNCTION isliked(pid INT, uid INT)
RETURN TABLE
AS
RETURN (EXISTS (SELECT 1 FROM likedata ld WHERE post_id = pid AND user_id = uid
       )) as is_liked
END

我试着用下面的问题来称呼它：

SELECT posts.id, posts.title, isliked(111,123)
FROM posts

它返回以下错误：

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'RETURN TABLE
AS
RETURN (EXISTS (SELECT 1 FROM likedata ld WHERE post_id = pid AN' at line 2

应该是这样的返回结果http://sqlfiddle.com/#!9/91040/5我是sql新手，任何帮助都会很好，提前谢谢