这个问题在这里已经有答案了：

mysql：将特定记录移到order by（4个答案）旁边的结果数组顶部
两年前关门了。
这段php代码从mysql打印出一个表。
如果id为“thisone”的行中有innerHTML2，我想将整行移到表的顶部，包括username kills和death，因为它们在同一行中对齐。
我认为这个mysql打印输出应该更好，但我真的不知道如何打印的东西属性这一个工作，尽管如此。
这张table看起来没碰过。如你所见，它的结尾有1和2。我要让第二组的所有行都移到最上面。
https://i.imgur.com/zkqrzcb.png

<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "username", "pw", "databasename");

// Check connection
if($link === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
}

// Attempt select query execution
$sql = "SELECT * FROM online_players";
if($result = mysqli_query($link, $sql)){
    if(mysqli_num_rows($result) > 0){
        echo "<table id='myTable'>";
            echo "<tr>";
                echo "<th>username</th>";
                echo "<th>kills</th>";
                echo "<th>deaths</th>";
                echo "<th>team</th>";
            echo "</tr>";
        while($row = mysqli_fetch_array($result)){
            echo "<tr>";
                echo "<td>" . $row['username'] . "</td>";
                echo "<td>" . $row['kills'] . "</td>";
                echo "<td>" . $row['deaths'] . "</td>";
                echo "<td id="thisone">" . $row['team'] . "</td>";
            echo "</tr>";
        }
        echo "</table>";
        // Free result set
        mysqli_free_result($result);
    } else{
        echo "No records matching your query were found.";
    }
} else{
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}

// Close connection
mysqli_close($link);
?>