如果我从数据库中选择了一个下拉列表值，那么标题值应该是显示的，例如我从下拉列表中选择了关于我们的页面，之后标题值应该是显示帮助我的任何一个
查看页面

<form class="form-horizontal" action="#" method="POST">
    <?php foreach ($seo_tag_update as $rows) { ?>
        <div class="form-group">
            <label class="col-sm-4 control-label">Select Pages:</label>
            <div class="col-sm-6">
                <select class="form-control" name="select_update_page" id="select_update_page">
                    <option value=""> -- select pages -- </option>
                    <?php
                    echo '<option value="' . $rows->page_id . '">' . $rows->page_name . '</option>';
                    ?>  
                </select>

            </div>
        </div>

        <div class="form-group">
            <label class="col-sm-4 control-label">Title:</label>
            <div class="col-sm-6">   
                <input type="text" class="form-control" name="update_title" id="update_title " value="<?php echo $rows->page_title; ?>">
            </div>
        </div>

    </div><?php } ?>
<div class="form-group">
    <div class="col-md-offset-4 col-sm-6">
        <button class="btn btn-sumit">SUBMIT</button>
    </div>
</div>
</form>

控制器

public function update() {
$this->load->helper('url');
$data['seo_tag_update'] = $this->Question_Insertion_Model->seo_tag_Update();
echo "$posted_id";
$this->load->view('update', $data);
}

模型

public function seo_tag_Update() {
$this->db->select('*');
$this->db->from('kas_all_pages s');
$this->db->join('kas_all_pages_tags q','s.page_id=q.page_fk');
$this->db->where('s.page_id', 1);
$query = $this->db->get();
return $result = $query->result();
}