这是我要修改的查询
select
o.orders_id,
o.customers_id,
o.customers_name,
s.orders_status_name,
ot.text as order_total,
ot.value as value,
datediff(now(), payment_data_read_status) as numdaysleft,
sum(ifnull(op.paid_total, 0)) paid_total
from orders o
join orders_total ot
on o.orders_id = ot.orders_id
join orders_status s
on o.orders_status = s.orders_status_id
left outer join ( select orders_id, sum(ifnull(paid_amount, 0)) as paid_total from orders_payment where confirm_payment = '1' group by orders_id ) op on op.orders_id = o.orders_id where ot.class = 'ot_total' and s.language_id = '1' and round(ot.value,2) != round(ifnull(op.paid_total, 0), 2)
GROUP by o.customers_id
ORDER BY paid_total DESC
每个客户都有自己的订单,订单完成、注入、等待付款确认等不同的状态,我想实现的是对订单价值的求和 ot.value
对于每个客户的所有订单 s.orders_status_name
=“订单完成”并在新列中显示为“已完成订单总数”。同样地,未处于“订单完成”状态的订单也应相加 ot.value
并在新列中显示为“未完成订单和”
这是每个客户机的数据
1条答案
按热度按时间fjaof16o1#
你需要一个
.