我有一个json数组,如下所示:
{
"operation": "update_original_team_member",
"teamMember": {
"teamMemberPresent": false,
"unique_id": "5a5b7f6b835408.50059003",
"user_unique_id": "59bea8b7d56a63.33388595"
}
}
我试着把它插入mysql数据库,但是每次都失败了,但是当我把false改为true时,它就成功了,你知道为什么吗?
插入的表格如下:
CREATE TABLE team_member (
team_member_id int(11) NOT NULL AUTO_INCREMENT,
unique_id varchar(23) NOT NULL,
fullName varchar(50) NOT NULL,
user_unique_id varchar(23) NOT NULL,
present boolean NOT NULL,
date_last_present datetime DEFAULT NULL,
points int(50) NULL,
team_id int (11) NOT NULL,
PRIMARY KEY (team_member_id),
FOREIGN KEY (`team_id`)
REFERENCES `ocidb_CB9s149919`.`team` (`team_id`)
);
json数组是从Reformation(Reformation是android的rest客户端)发送的,接收方式如下:
if ($operation == 'update_original_team_member') {
if (isset($data -> teamMember) && !empty($data -> teamMember)&& isset($data -> teamMember -> teamMemberPresent)
&& isset($data -> teamMember -> unique_id)&& isset($data -> teamMember -> user_unique_id)){
$teamMember = $data -> teamMember;
$teamMemberPresent = $teamMember -> teamMemberPresent;
$unique_id = $teamMember -> unique_id;
$user_unique_id = $teamMember -> user_unique_id;
echo $fun -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);
} else {
echo $fun -> getMsgInvalidParam();
}
这将传递给以下函数:
public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){
$db = $this -> db;
if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){
$result = $db -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);
if ($result) {
$response["result"] = "success";
$response["message"] = "Active Students Have Been Recorded!";
return json_encode($response);
} else {
$response["result"] = "failure";
$response["message"] = "Unable To Update Details, Please Try Again";
return json_encode($response);
}
} else {
return $this -> getMsgParamNotEmpty();
}
}
我用来更新的查询是:
public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){
$sql = "UPDATE team_member SET present = :present WHERE unique_id = :unique_id AND user_unique_id = :user_unique_id";
// Prepare statement
$query = $this ->conn ->prepare($sql);
// execute the query
$query->execute(array(':present' => $teamMemberPresent,':unique_id' => $unique_id, ':user_unique_id' => $user_unique_id));
if ($query) {
return true;
} else {
return false;
}
}
我用 Postman 试图把问题隔离开来,我把范围缩小到 $teamMemberPresent
变量失败,说明它是空的,当它是错的,但我不知道为什么。如前所述,当设置为true时,查询工作正常。
任何指导都将不胜感激。
2条答案
按热度按时间nafvub8i1#
将布尔变量转换为int。
bhmjp9jg2#
在你的
updatePresent()
函数时,此代码不会将数据识别为有效数据,并跳过数据库更新:原因是
empty($teamMemberPresent)
如果其参数具有false
价值观。http://php.net/empty 说:
如果变量不存在或其值等于false,则认为该变量为空。
你应该使用
isset($teamMemberPresent)
相反。下面是一个演示:
输出: