您可以用需要比较的变量（100200300400）创建一个额外的表。然后你可以一起数数。
这并不漂亮，但这里有一个例子：http://sqlfiddle.com/#!9/3f906c/1号

因此，使用集合可以执行以下操作：
在数组/集合中定义开始日期

$dates = collect(['2018-09-10', '2018-09-18', '2018-09-16', '2018-09-15']);

你可以用这个 whereIn('start', $dates) ```
$result = Availability::...
$collection = $dates->map(function($item) use($result) {
return ['count' => $result->firstWhere('start', $item)['count'] ?? 0, // in case line does not work use optional($result->firstWhere('start', $item))->count ?? 0,
'start' => $item];
});

dd($collection); // your desired result

我和tinker一起玩，所以这里是最后的tinker课程：

$a = collect([['count' => 1, 'start' => '2018-09-10'], ['count' => 3, 'start' => '2018-09-11']])
=> Illuminate\Support\Collection {#828
all: [
[
"count" => 1,
"start" => "2018-09-10",
],
[
"count" => 3,
"start" => "2018-09-11",
],
],
}
$b = collect(['2018-09-10', '2018-09-11', '2018-10-14'])
=> Illuminate\Support\Collection {#809
all: [
"2018-09-10",
"2018-09-11",
"2018-10-14",
],
}
$b->map(function($item) use($a) {return ['count' => $a->firstWhere('start', $item)['count'] ?? 0, 'start' => $item];});
=> Illuminate\Support\Collection {#832
all: [
[
"count" => 1,
"start" => "2018-09-10",
],
[
"count" => 3,
"start" => "2018-09-11",
],
[
"count" => 0,
"start" => "2018-10-14",
],
],
}