这是我的table。
Financials:
Date
CountryID
ProductID
Revenue
Cost
我需要找出每个国家收入前五名的产品。有些产品会多次上市,所以我需要为每个产品的收入加总。
SELECT
Financials.CountryID,
Financials.ProductID,
SUM(Financials.Revenue) AS total
FROM Financials
INNER JOIN (SELECT
CountryID,
GROUP_CONCAT (ProductID ORDER BY Revenue DESC) grouped_ID
FROM Financials
GROUP BY CountryID) group_max
ON Financials.CountryID = group_max.CountryID
AND FIND_IN_SET(ProductID, grouped_ID) BETWEEN 1 AND 6
GROUP BY Financials.ProductID
ORDER BY Financials.CountryID, total DESC
这就是我目前所知道的。它不起作用。救命啊?
编辑
我一直在用https://sqltest.net/. 请参阅下面的插入命令
CREATE TABLE mysql_test (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
CountryID VARCHAR(30) NOT NULL,
ProductID VARCHAR(30) NOT NULL,
Revenue VARCHAR(50),
cost VARCHAR(50),
reg_date TIMESTAMP
);
CREATE TABLE mysql_test_sql (
id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
CountryID VARCHAR(30) NOT NULL,
ProductID VARCHAR(30) NOT NULL,
Revenue VARCHAR(50),
cost VARCHAR(50),
reg_date TIMESTAMP
);
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('1', 'Canada', 'Doe', '20', '5', '2010-01-31 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('2', 'USA', 'Tyson', '40', '15', '2010-02-14 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('3', 'France', 'Keaton', '80', '25', '2010-03-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('4', 'France', 'Joe', '180', '45', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('5', 'France', 'Bill', '30', '6', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('6', 'France', 'Emma', '15', '2', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('7', 'France', 'Joe', '60', '36', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('8', 'France', 'Jammer', '130', '26', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('9', 'France', 'Louis', '350', '12', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('10', 'France', 'dennis', '100', '175', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('11', 'USA', 'zooey', '70', '16', '2010-04-25 12:01:01');
INSERT INTO `mysql_test` (`id`, `CountryID`, `ProductID`, `Revenue`, `cost`, `reg_date`) VALUES ('12', 'France', 'Alex', '2', '16', '2010-04-25 12:01:01');
1条答案
按热度按时间eoxn13cs1#
这里有一种方法:
注意:对于的中间结果,默认的内部限制为1028个字符
group_concat()
. 每个国家最多可以生产几百种产品。默认长度是系统设置,可以更改。