我尝试从3个表Map一个实体,使用@entity、@table、@secondarytables和@column注解,如下例所示。
这些表格是:1。员工(主要)2。员工详细信息3。工作描述
@Entity
@Table(name="EMPLOYEE")
@SecondaryTables({
@SecondaryTable(name="EMPLOYEE_DETAIL",
pkJoinColumns = @PrimaryKeyJoinColumn(name="EMPLOYEE_ID")),
@SecondaryTable(name="JOB_DESCRIPTION",
pkJoinColumns = @PrimaryKeyJoinColumn(name="JD_ID"))
})
public class Employee {
@Id
@Column(name = "ID", table= "EMPLOYEE")
private int id;
@Column(name = "FIRST_NAME", table = "EMPLOYEE")
private String firstname;
@Column(name = "LAST_NAME", table = "EMPLOYEE")
private String lastname;
@Column(name = "BANK_ACCOUNT_NO", table = "EMPLOYEE_DETAIL")
private String bankacctnumber;
@Column(name = "JOB_SUMMARY", table = "JOB_DESCRIPTION")
private String jobsummary;
@Column(name = " ??? ", table = " ?? ")
private String uniqueid;
//getters and setters for above fields
...
}
我的问题是,如果我想通过连接创建字段“uniqueid”
表“employee”中的“id”列和表“job\u description”中的“job\u code”列
此实体与以下sql查询字符串相对应(为了清楚起见,我使用了字符串生成器):-
StringBuilder sql = new StringBuilder();
sql.append("SELECT");
sql.append(" e.FIRST_NAME AS firstname,");
sql.append(" e.LAST_NAME AS lastname,");
sql.append(" d.BANK_ACCT_NUMBER AS bankacctnumber,");
sql.append(" j.JOB_SUMMARY AS jobsummary,");
sql.append(" CONCAT(e.ID,SUBSTR(j.JOB_CODE,3,8)) AS uniqueid");
sql.append(" FROM employee e");
sql.append(" LEFT JOIN employee_detail d ON d.EMPLOYEE_ID = e.ID");
sql.append(" LEFT JOIN job_description j ON j.JD_ID = e.JD_ID ");
sql.append(" WHERE e.ID = 1 ");
究竟应该如何为字段“uniqueid”Map列?这可能吗?
1条答案
按热度按时间dkqlctbz1#
不,这是不可能的,因为jpa正在使用Map列进行读写。所以列不能连接。
但是您可以在类中编写一个简单的方法来连接字段。
另一种可能是使用sql语句的视图,但由于该视图包含多个表的字段,因此只能进行读写操作。