如果没有所有中间值，如何在同一天获得第一个输入和最后一个输出

9cbw7uwe 于 2021-06-25 发布在 Mysql

关注(0)|答案(1)|浏览(264)

我的问题是：

SELECT id, employee_number, MAX(time_in_out)
FROM raw_attendance
GROUP BY id

结果是：

mysql

来源：https://stackoverflow.com/questions/48198976/how-can-i-get-the-1st-in-and-last-out-without-all-the-middle-value-on-the-same-d

1条答案

按热度按时间

xpcnnkqh1#

SELECT
id,
  employee_number,
 date(ra.time_in_out) as as_of_date,
      (SELECT
          time_in_out
        FROM raw_attendance rmax
        WHERE (rmax.time_in_out)= (ra.time_in_out)
        ORDER BY time_in_out DESC LIMIT 1) AS max_time,
      (SELECT
          time_in_out
        FROM raw_attendance rmin
        WHERE (rmin.time_in_out)=(ra.time_in_out)
        ORDER BY time_in_out ASC LIMIT 1) AS min_time

FROM raw_attendance ra
GROUP BY date(ra.time_in_out)

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如果没有所有中间值，如何在同一天获得第一个输入和最后一个输出

1条答案

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