我正在用 Spring Boot
以及 Spring Data JPA
.
以下为相关实体:
@Entity
public class Certification {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "certification_type_id")
private CertificationType certificationType;
@OneToMany(fetch = FetchType.EAGER, mappedBy = "certification", cascade = CascadeType.ALL)
private Set<CertificationStatus> certificationStatuses;
}
@Entity
public class CertificationType {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@Enumerated(EnumType.STRING)
private Code code;
private String name;
private String description;
...
public enum Code {
...
}
}
@Entity
public class CertificationStatus {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@ManyToOne
@JoinColumn(name = "certification_id")
private Certification certification;
@ManyToOne
@JoinColumn(name = "certification_status_type_id")
private CertificationStatusType certificationStatusType;
private String remarks;
}
@Entity
public class CertificationStatusType {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer id;
@Enumerated(EnumType.STRING)
private Code code;
private String name;
private String description;
@OneToMany(fetch = FetchType.EAGER, mappedBy = "certificationStatusType", cascade = CascadeType.ALL)
private Set<CertificationStatus> certificationStatuses;
public enum Code {
...
}
}
在我的服务中,我有一个方法, CertificationService.findAll()
. 我们的想法是 certification
最新记录 certification_status
基于 MAX(id)
, GROUP BY certification_id
以及 WHERE certification_status_type_id = ?
. 此方法有五(5)个参数:
Integer certificationTypeId,
Integer certificationStatusTypeId,
LocalDate dateFrom,
LocalDate dateTo,
String client
组合可以是0到5。因此,我选择应用jpa标准。到目前为止,我已经编写了以下代码:
@Override
public List<CertificationDto> findAll(
Integer certificationTypeId,
Integer certificationStatusTypeId,
LocalDate dateFrom,
LocalDate dateTo,
String client) {
var certifications = this.certificationRepository.findAll((root, criteriaQuery, criteriaBuilder) -> {
var predicates = new ArrayList<Predicate>();
// This is working
if (certificationTypeId != null && certificationTypeId > 0) {
predicates.add(criteriaBuilder.and(criteriaBuilder.equal(root.join(Certification_.certificationType, JoinType.INNER), certificationTypeId)));
}
// To do
if (certificationStatusTypeId != null && certificationStatusTypeId > 0) {
/*
* I have no idea how to apply my SQL statement:
* SELECT * FROM certification_status WHERE id IN (SELECT MAX(id) FROM certification_status GROUP BY certification_id) and certification_status_type_id = ?;
*/
// Not sure what is the direction of the ff codes
var certificationStatuses = root.join(Certification_.certificationStatuses);
predicates.add(criteriaBuilder.and(criteriaBuilder.max(certificationStatuses.get(CertificationStatus_.id))));
// It says Cannot resolve method 'and(javax.persistence.criteria.Expression<N>)'
// Not also sure how to pass in parameter certificationStatusTypeId
}
// This is working
if (dateFrom != null) {
var offsetDateTimeFrom = OffsetDateTime.of(dateFrom, LocalTime.MIDNIGHT, ZoneOffset.ofHours(8));
var dateTimeFrom = Date.from(offsetDateTimeFrom.toInstant());
var offsetDateTimeTo = OffsetDateTime.of(Objects.requireNonNullElse(dateTo, dateFrom), LocalTime.MAX, ZoneOffset.ofHours(8));
var dateTimeTo = Date.from(offsetDateTimeTo.toInstant());
predicates.add(criteriaBuilder.and(criteriaBuilder.between(
root.get(Certification_.createdAt),
criteriaBuilder.literal(dateTimeFrom),
criteriaBuilder.literal(dateTimeTo)))
);
}
// This is working
if (client != null && !client.isBlank()) {
predicates.add(criteriaBuilder.and(criteriaBuilder.like(criteriaBuilder.lower(root.join(Certification_.client).get(Client_.name)), "%" + client.toLowerCase() + "%")));
}
return criteriaBuilder.and(predicates.toArray(new Predicate[0]));
});
return certifications.stream()
.map(this.certificationMapper::fromEntityToDto)
.collect(Collectors.toUnmodifiableList());
}
我的标准 certificationTypeId
, dateFrom
, dateTo
,和 client
你在工作。对于 certificationStatusTypeId
,我要基于以下sql语句创建条件:
SELECT * FROM certification_status WHERE id IN (SELECT MAX(id) FROM certification_status GROUP BY certification_id) and certification_status_type_id = ?;
此语句在数据库中起作用。但不确定这是否是选择记录所基于的查询的最佳组合 MAX(id)
, GROUP BY certification_id
以及 WHERE certification_status_type_id = ?
.
谢谢你的帮助。谢谢您。
**更新
这是我的代码:
if (certificationStatusTypeId != null && certificationStatusTypeId > 0) {
Subquery<Long> subQuery = criteriaQuery.subquery(Long.class);
Root<CertificationStatus> subRoot = subQuery.from(CertificationStatus.class);
subQuery.select(criteriaBuilder.max(subRoot.get(CertificationStatus_.id)))
.groupBy(subRoot.get(CertificationStatus_.certification).get(Certification_.id));
predicates.add(criteriaBuilder.and(criteriaBuilder.in(subRoot.get(CertificationStatus_.id)).value(subQuery)));
predicates.add(criteriaBuilder.and(criteriaBuilder.equal(subRoot.get(CertificationStatus_.certificationStatusType).get(CertificationStatusType_.id), certificationStatusTypeId)));
}
但它会抛出以下错误:
org.hibernate.hql.internal.ast.QuerySyntaxException: Invalid path: 'generatedAlias1.id' [select generatedAlias0 from entity.Certification as generatedAlias0 where ( generatedAlias1.id in (select max(generatedAlias1.id) from entity.CertificationStatus as generatedAlias1 group by generatedAlias1.certification.id) ) and ( generatedAlias1.certificationStatusType.id=2 )]; nested exception is java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: Invalid path: 'generatedAlias1.id' [select generatedAlias0 from entity.Certification as generatedAlias0 where ( generatedAlias1.id in (select max(generatedAlias1.id) from entity.CertificationStatus as generatedAlias1 group by generatedAlias1.certification.id) ) and ( generatedAlias1.certificationStatusType.id=2 )]
查看生成的jpql,它看起来与我的sql语句类似。我只是不明白为什么 Invalid path
.
**更新我的道歉!我的sql语句实际上类似于:
select
// props of Certification
from certification c
inner join certification_type ct on ct.id = c.certification_type_id
inner join client cl on cl.certification_id = c.id
inner join certification_status cs on cs.certification_id = c.id
inner join certification_status_type cst on cst.id = cs.certification_status_type_id
where cs.id in (select max(cs2.id) form certification_status cs2 group by cs2.certification_id) and cs.certification_status_type_id = ?;
更新
这就解决了。多亏了 Thorben Janssen
感谢你耐心地调查我的问题。
这是我代码的最后一部分:
if (certificationStatusTypeId != null && certificationStatusTypeId > 0) {
var certificationStatuses = root.join(Certification_.certificationStatuses);
Subquery<Long> subQuery = criteriaQuery.subquery(Long.class);
Root<CertificationStatus> subRoot = subQuery.from(CertificationStatus.class);
subQuery.select(criteriaBuilder.max(subRoot.get(CertificationStatus_.id)))
.groupBy(subRoot.get(CertificationStatus_.certification).get(Certification_.id));
predicates.add(criteriaBuilder.and(certificationStatuses.get(CertificationStatus_.id).in(subQuery)));
predicates.add(criteriaBuilder.and(criteriaBuilder.equal(certificationStatuses.get(CertificationStatus_.certificationStatusType).get(CertificationStatusType_.id), certificationStatusTypeId)));
}
1条答案
按热度按时间nszi6y051#
下面的代码段创建了一个与sql语句相同的criteriaquery。因为您使用的是springdatajpa,所以可以忽略第一个块和最后一行。springdatajpa为您提供了它们。
可以通过调用
subquery
你的方法CriteriaQuery
. 返回一个Subquery
接口,您可以使用相同的方式作为CriteriaQuery
接口。在你定义你的
Subquery
,您可以定义in子句并将其包含在查询的where子句中。这部分看起来总是有点奇怪。而不是使用CriteriaBuilder
定义Expression
,则获取实体属性并调用in
方法,并参考Subquery
.在最后一步中,使用
CriteriaQuery
示例化TypedQuery
然后执行它。激活sql语句日志记录后,可以看到hibernate执行以下sql语句:**更新
在定义in子句时,似乎引用了错误的表。请尝试更换
具有