你可以分解数组，释放值，再收集数组。演示：

with your_table as(
select stack(2,
 1 , array('0', '0', '1', '0', '1', '1', '0', '0'),
 2 , array('2', '0', '3', '0', '3', '1', '2', '1')
 ) as (id,value)
 ) --use your_table instead of this

 select s.id, 
        s.value                            as original_array, 
        collect_list(cast(s.str as float)) as array_float 
 from
(select t.*, s.* 
 from your_table t
               lateral view outer posexplode(t.value)s as pos,str       
   distribute by t.id, t.value 
         sort by s.pos --preserve order in the array
 )s  
group by s.id, s.value;

结果：

OK
1       ["0","0","1","0","1","1","0","0"]       [0.0,0.0,1.0,0.0,1.0,1.0,0.0,0.0]
2       ["2","0","3","0","3","1","2","1"]       [2.0,0.0,3.0,0.0,3.0,1.0,2.0,1.0]

另请参阅这个关于在查询中排序数组的答案https://stackoverflow.com/a/57392965/2700344