如何将3个表上的3个select语句的结果插入到配置单元中的新表中？

jaxagkaj 于 2021-06-28 发布在 Hive

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select sum(column_table1) from table1 where job_run_time_stamp >= '2016-12-15 00:00:00' and job_run_time_stamp < '2016-12-16 00:00:00';
select sum(column_table2) from table2 where job_run_time_stamp >= '2016-12-15 00:00:00' and job_run_time_stamp < '2016-12-16 00:00:00';
select sum(column_table3) from table3 where job_run_time_stamp >= '2016-12-15 00:00:00' and job_run_time_stamp < '2016-12-16 00:00:00';

如何组合上述3个查询结果并将它们放入名为 table4 在 hive 里？

Hive select Insert

来源：https://stackoverflow.com/questions/41167747/how-can-i-insert-the-result-of-3-select-statements-on-3-tables-into-a-new-table

1条答案

按热度按时间

h43kikqp1#

以下方法可以奏效

insert into table4
values(
select sum(t.sum1) , sum(t.sum2), sum(t.sum3) from 
(select sum(column_table1) as sum1 , 0 as sum2, 0 as sum3 from table1 where     job_run_time_stamp >= '2016-12-15 00:00:00' and job_run_time_stamp < '2016-12-16 00:00:00'
union
select 0, sum(column_table2) , 0 from table2 where job_run_time_stamp >= '2016-12-15 00:00:00' and job_run_time_stamp < '2016-12-16 00:00:00' 
union
select 0,0, sum(column_table3) from table3 where job_run_time_stamp >= '2016-12-15 00:00:00' and job_run_time_stamp < '2016-12-16 00:00:00') as t
)

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如何将3个表上的3个select语句的结果插入到配置单元中的新表中？

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