java—如何解决以下与jtable的动态排序和选择相关的问题?

ru9i0ody  于 2021-06-29  发布在  Java
关注(0)|答案(0)|浏览(241)

我正在使用jtable的动态排序代码。问题是,我一输入,表就显示正确的响应,一秒钟后,它就返回到以前的原始状态。如何纠正这个问题?

private void jTextField2KeyReleased(java.awt.event.KeyEvent evt) {                                        
        // TODO add your handling code here:
        DefaultTableModel model = (DefaultTableModel) jTable1.getModel();
        TableRowSorter<TableModel> rowSorter = new TableRowSorter<>(jTable1.getModel());
        jTable1.setRowSorter(rowSorter);
        jTextField2.getDocument().addDocumentListener(new DocumentListener() {

            @Override
            public void insertUpdate(DocumentEvent e) {
                String text = jTextField2.getText();

                if (text.trim().length() == 0) {
                    rowSorter.setRowFilter(null);
                } else {
                    rowSorter.setRowFilter(RowFilter.regexFilter("(?i)" + text));
                }
            }

            @Override
            public void removeUpdate(DocumentEvent e) {
                String text = jTextField2.getText();

                if (text.trim().length() == 0) {
                    rowSorter.setRowFilter(null);
                } else {
                    rowSorter.setRowFilter(RowFilter.regexFilter("(?i)" + text));
                }
            }

            @Override
            public void changedUpdate(DocumentEvent e) {
                throw new UnsupportedOperationException("Not supported yet."); //To change body of generated methods, choose Tools | Templates.
            }

        });
    }

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