我的申请有问题。我用java创建一个html文件，然后使用requestdispatcher将其转发给客户机。客户端输入坐标，点击一个按钮，就会得到新的html。取而代之的是，当我点击时，我得到了该html的前一个版本（它应该根据输入而改变），然后每次我刷新时，什么都没有改变。文件正在本地更新。我尝试删除缓存，状态是200 ok，但仍然显示以前版本的html。以下是我的java：
class CreateHtml {
public void createHtml() throws IOException {
File f = new File("distance.html");
BufferedWriter bw = new BufferedWriter(new FileWriter(f));
File file = new File("rastojanija.txt");
BufferedReader br = new BufferedReader(new FileReader(file));
String line = br.readLine();
bw.write("<html><body style=\"height: 97%;"
+ "background-image: url(slikiApp/pozadina_mapa_burred.jpg); background-size: cover; background-repeat: no-repeat;"
+ "font-family: 'Trebuchet MS', sans-serif\">"
+ "<a href=\"home.html\"><img src=\"slikiApp/levo_strelka.png\" style=\"float:left; height:15%; width:10%; cursor:pointer\"></a><img style=\"display:block; margin-left:auto; margin-right:auto; width: 30%\" id=\"logoDistance\" src=\"slikiApp/logo_shadow.png\"><div id=\"distanceContainer\""
+ "style=\"margin:auto; margin:auto; height:65%; width:50%; padding:10px\" id=\"distanceContainer\">\r\n");
while (line != null) {
System.out.println("LINE"+line); //here is everything ok, it prints what should be in the html
bw.write("<p style=\"font-size:3vw; margin-left:10px\">" + line
+ "</p><div style=\"margin-top: -95px; margin-left:475px\"><img onclick=\"addToVisited()\" style=\"height:16%; width:26%; cursor:pointer\" src=\"slikiApp/pin_shadow.png\"><img onclick=\"addToFaves()\" style=\"height:16%; width:37%; cursor:pointer\" src=\"slikiApp/favourites.png\"></div>");
bw.write("<br>");
line = br.readLine();
}
br.close();
bw.write("</div></body></html>");
bw.close();
}
}
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
response.setContentType("text/html");
String value = (String) request.getParameter("input1");
mainFunc(value);
CreateHtml html = new CreateHtml();
html.createHtml();
String nextHTML = "/distance.html";
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(nextHTML);
dispatcher.forward(request, response);
}谢谢您！
1条答案
按热度按时间2guxujil1#
您可能遇到浏览器缓存问题。
您可以直接将html流式传输到响应，而不是转发
如果确实需要写入该文件并将客户端转发给它，可以尝试通过添加一个伪get参数来“破坏”浏览器缓存逻辑，例如转发到
"/distance.html?t=" + System.currentTimeMillis()