目标是创建一个大小为100的数组，让用户输入一组正数，然后在输入-1时退出（或者填充100个点）。之后，打印出读取的输入数、平均值和最高值。我最初是用一个较小的数组来测试我的代码，以获得平均值，现在我意识到array.length不是我想要的，因为我将它切换到100并且不填充100个插槽。我的问题是，如何计算输入到数组中的输入量，而不仅仅是数组的总长度？

import java.util.*;
class Array{
    public static void main(String [] args){
       Scanner scan = new Scanner(System.in);
       int[] array = new int[100];

       System.out.println("Enter your number: ");
       for(int i = 0; i < 100; i++){
          int entry = scan.nextInt();
          if(entry == -1){
             System.out.println("Goodbye.");
             i--;
             break;
          }else if(entry < -1){
             System.out.println("Invalid.");
             i--;
          }else{
             array[i] = entry;
          }
       } 
       //prints amount of elements inside array
       //System.out.println("There are " + countArray(array) + " numbers in this array.");

       //prints average
       System.out.println("The average is: " + findAverage(array));   

       //prints highest val
       System.out.println("The highest value is: " + findHigh(array));

    }
    //public static int countArray(int[] array)
    //need help here and then fixing the issue in the average method

     public static double findAverage(int [] array){
         double sum = 0;
         for(int i = 0; i < array.length; i++){
            sum += array[i];
         }
         double average = (sum/array.length);
         return average;
      }

      public static int findHigh(int[]array){
         int max = array[0];
         for(int i = 1; i < array.length; i++){
            if (array[i] > max){
               max = array[i];
            }
         } 
         return max;
      }  
}