我需要将json文件序列化为java对象。json文件有一个树结构,这意味着根对象有自己的子对象,以此类推。例如,考虑以下json文件:
{
"name": "peter",
"parent": null,
"children": [
{
"name": "simon",
"parent": "peter",
"children": [
{
"name": "john",
"parent": "simon",
"children": []
}
]
},
{
"name": "javier",
"parent": "peter",
"children": []
},
{
"name": "martin",
"parent": "peter",
"children": []
}
]
}
我试过使用jackson库进行序列化。这是我要序列化到的对象:
public class Person {
private String name;
private Person parent;
private List<Person> children;
@JsonCreator
public Project(@JsonProperty("name") String name,
@JsonProperty("parent") Person parent,
@JsonProperty("children") List<Person> children) {
this.name = name;
this.coordinates = parent;
this.children = children;
}
// getters, setters, and constructor
}
这就是我迄今为止所尝试的:
String jsonString = Files.readString(Paths.get("/path_to/file.json"));
List<Person> listModel = objectMapper.readValue(jsonString, new TypeReference<>() {});
但是,它会触发以下事件 MismatchedInputException: Cannot deserialize instance of java.util.ArrayList<Person> out of START_OBJECT token
.
1条答案
按热度按时间ua4mk5z41#
无法反序列化java.util.arraylist示例的起始\u对象标记。因为json文件是person对象而不是list对象