这个问题在这里已经有答案了:
整数除法:为什么1/3的结果==0((16个答案)
24天前关门。
我的程序允许用户计算两个数字,然后根据用户输入的运算符执行简单的计算。所以我的源代码是:
System.out.print("Enter First Number: ");
int num1 = scanNum.nextInt();
System.out.print("Enter Second Number: ");
int num2 = scanNum.nextInt();
System.out.print("Enter Operator (+, -, * or /): ");
char opt = scanOpt.next().charAt(0);
scanNum.close();
scanOpt.close();
switch (opt)
{
case '+':
float result = num1 + num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
case '-':
result = num1 - num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
case '*':
result = num1 * num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
case '/':
result = num1 / num2;
System.out.println(num1 + " " + opt + " " + num2 + " = " +result);
break;
default:
System.out.println("Invalid Operator!");
break;
它工作得很好,但是每当它将两个数字相除时,比如“6.0/4.0”,第十个小数点就不会出现。正确的输出应该是:
Enter First Number: 6
Enter Second Number: 4
Enter Operator (+, -, * or /): /
6 / 4 = 1.5
但使用我自己的源代码,结果是:
Enter First Number: 6
Enter Second Number: 4
Enter Operator (+, -, * or /): /
6 / 4 = 1.0
2条答案
按热度按时间von4xj4u1#
34gzjxbg2#
这是因为java将两个整数相除,从而得到一个整数输出。尝试将输入声明为float或alternativeley
这会将num1“转换”为浮点值。