我想用字符串变量代替url调用中的ip地址。我想在应用程序中用ip地址和端口号登录。然后我想在共享首选项中保存这个ip地址,然后在url调用中我想在共享首选项中使用那个存储ip地址
我得到这样的共享首选项的ip地址。
SharedPreferences pref = getActivity().getSharedPreferences("MyPref", MODE_PRIVATE);
ip= pref.getString("key_ip", null); // getting Float
Log.e("ip: ", "> " + ip);
然后我使用如下方法调用url。
public static String off33() {
StringBuffer stringBuffer = new StringBuffer("");
BufferedReader bufferedReader = null;
try {
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet();
URI uri = new URI("http://10.1.1.82:80/outlet?3=ON");
httpGet.setURI(uri);
httpGet.addHeader(BasicScheme.authenticate(
new UsernamePasswordCredentials("admin", "kirti123"),
HTTP.UTF_8, false));
HttpResponse httpResponse = httpClient.execute(httpGet);
InputStream inputStream = httpResponse.getEntity().getContent();
bufferedReader = new BufferedReader(new InputStreamReader(
inputStream));
String readLine = bufferedReader.readLine();
while (readLine != null) {
stringBuffer.append(readLine);
stringBuffer.append("\n");
readLine = bufferedReader.readLine();
}
} catch (Exception e) {
// TODO: handle exception
} finally {
if (bufferedReader != null) {
try {
bufferedReader.close();
} catch (IOException e) {
// TODO: handle exception
}
}
}
return stringBuffer.toString();
}
所以,我想在方法10.1.1.82中使用ip字符串代替url,这意味着我想这样使用。
URI uri = new URI("http://ip:80/outlet?3=ON");
ip是一个字符串变量,在这个变量中我得到10.1.1.82
所以我怎么不能用这个?
2条答案
按热度按时间q9yhzks01#
您也可以这样做:
biswetbf2#
只需连接字符串