使用线程输入

nwnhqdif 于 2021-07-03 发布在 Java

关注(0)|答案(3)|浏览(282)

import java.util.Scanner;

public class ThreadClass {

    public static void main(String[] args) 
    {
        System.out.println("Type the following in 5 seconds");
        System.out.println("The quick brown fox jumps over the lazy dog");

        try {
            Scanner sc = new Scanner(System.in);
            String str=sc.nextLine();
            Thread.sleep(1000);
            System.out.println("Your time is over");

        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

    }
}

在上面的程序中，我希望我的程序应该要求用户在5秒（或5000毫秒）内输入，并且应该在时间结束后自动关闭并显示一条消息“您的时间结束了”。这段代码的问题在于，每当用户输入内容时，除非按下enter键，否则线程似乎不起作用。我试过在try-catch块外甚至线程下写扫描器代码，但似乎都不起作用。我认为问题出在我的scanner类上，但我无法解决如何以其他方式输入数据。

Java multithreading java.util.scanner

来源：https://stackoverflow.com/questions/37135654/input-using-thread

3条答案

按热度按时间

2nbm6dog1#

import java.util.Scanner;
import java.util.Timer;
import java.util.TimerTask;

public class Test {
    static volatile boolean isTimeCopleted = true;

    public static void main(String[] args) {
        Timer timer = new Timer();
        TimerTask task = new TimerTask() {

            @Override
            public void run() {
                if (isTimeCopleted) {
                    System.out.println("Your time is over");
                    System.exit(0);
                }
            }
        };
        timer.schedule(task, 5000);

        System.out.println("Type the following in 5 seconds");
        System.out.println("The quick brown fox jumps over the lazy dog");

        Scanner sc = new Scanner(System.in);
        String str = sc.nextLine();
        isTimeCopleted = false;

        System.out.println("Process Done");
        System.exit(0);
    }
}

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fnvucqvd2#

如果您的唯一动机是检查用户是否在5秒内插入了输入，那么为什么不通过计算时间来尝试这段代码呢

Scanner sc = new Scanner(System.in);
        long begantime = System.nanoTime();
        System.out.println("Enter something");
        String input = sc.nextLine();
        int totalTime = (System.nanoTime()-beganTime)/1000000000;
        if (time > 5)
            System.out.println("failed");
        else
            System.out.println(input);

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a0zr77ik3#

只是一个提示：您必须有两个线程-一个用于输入，另一个用于计时器。一旦计时器过期，中断输入线程。例如：

final Thread subject1 = new Thread(new Runnable() {

  public void run() {
    while (!Thread.interrupted()) {
      Thread.yield();
    }
    System.out.println("subject 1 stopped!");
  }
});
final Thread subject2 = new Thread(new Runnable() {

  public void run() {
    while (!Thread.interrupted()) {
      Thread.yield();
    }
    System.out.println("subject 2 stopped!");
  }
});
final Thread coordinator = new Thread(new Runnable() {

  public void run() {
    try {
      Thread.sleep(500);
    } catch (InterruptedException ex) { }
    System.out.println("coordinator stopping!");
    subject1.interrupt();
    subject2.interrupt();
  }
});
subject1.start();
subject2.start();
coordinator.start();

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使用线程输入

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