concat映像文件无法创建

4szc88ey 于 2021-07-03 发布在 Java

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我试着把两个图像连接起来。但不能创造它。
我无法理解下面代码中的问题是什么。
无法创建concat.jpg文件。

BufferedImage image = ImageIO.read(mainFile);
BufferedImage image1 = ImageIO.read(fileToMerge);
int width = Math.max(image.getWidth() , image1.getWidth());
int height = Math.max(image.getHeight() , image1.getHeight());
log.info("width {}", width);
log.info("height {}", height);
BufferedImage concatImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_ARGB);
Graphics2D graphics2D = concatImage.createGraphics();
graphics2D.drawImage(image, 0, image.getHeight(), null);
graphics2D.drawImage(image1, 0 , image1.getHeight(), null);
ImageIO.write(concatImage, "jpg", new File(Constants.LOCAL_FOLDER + "/concat.jpg"));

Java

来源：https://stackoverflow.com/questions/65142601/concat-image-file-not-able-to-create

1条答案

按热度按时间

rjee0c151#

你想要的是 concatImage 等于 image 以及 image1 .
你想画画吗 image 在坐标（0,0）处绘制 image1 在x=0和y= image 请尝试以下操作。

BufferedImage image = ImageIO.read(mainFile);
BufferedImage image1 = ImageIO.read(fileToMerge);
int width = Math.max(image.getWidth() , image1.getWidth());
int height = image.getHeight() + image1.getHeight();
log.info("width {}", width);
log.info("height {}", height);
BufferedImage concatImage = new BufferedImage(width, height, BufferedImage.TYPE_INT_ARGB);
Graphics2D graphics2D = concatImage.createGraphics();
graphics2D.drawImage(image, 0, 0, null);
graphics2D.drawImage(image1, 0, image.getHeight(), null);
ImageIO.write(concatImage, "jpg", new File(Constants.LOCAL_FOLDER + "/concat.jpg"));

注意你应该打电话 graphics2D.dispose() 当你不再需要使用它的时候。

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concat映像文件无法创建

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