spring启动:nosuchbeandefinitionexception

nuypyhwy  于 2021-07-04  发布在  Java
关注(0)|答案(1)|浏览(458)

我对spring boot应用程序有问题:

spring.bat init --artifactId=dbproto4 --boot-version=2.1.7.RELEASE --dependencies=jdbc,data-rest,web,thymeleaf,devtools,lombok,configuration-processor,security,data-jpa,data-jdbc,postgresql,actuator --description=dbproto4 --groupId=com.test --java-version=11 --name=dbproto4 --package-name=com.test.dbproto4 --version=0.0.1-SNAPSHOT

这是一个例外:

Exception in thread "restartedMain" java.lang.reflect.InvocationTargetException
    at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.base/java.lang.reflect.Method.invoke(Method.java:566)
    at org.springframework.boot.devtools.restart.RestartLauncher.run(RestartLauncher.java:49)
Caused by: org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'testService' available

所有文件都在应用程序根目录中
DBProto4应用程序:
@springbootplication公共类dbproto4application{

public static void main(String[] args) {
    SpringApplication.run(Dbproto4Application.class, args);

    ApplicationContext javaConfigContext = new AnnotationConfigApplicationContext(SpringConfig.class);
    TestService testServiceObj = (TestService) javaConfigContext.getBean("testService");        
    testServiceObj.addNewUser();

Spring配置:

@EnableJdbcRepositories(basePackages = "com.test.dbproto4.infrastructure.storage.jdbcrepos")
@Configuration
public class SpringConfig { }

用户:

@Entity
@Table(name = "userstab")
public class User {
    @Id
    @GeneratedValue(strategy=GenerationType.AUTO)
    private Integer id;

    private String name;

    private String email;

...

}

用户存储库:

public interface UserRepository extends CrudRepository<User, Integer> {

}

应用程序属性:

server.port = 8082

## default connection pool

spring.datasource.hikari.connectionTimeout=20000
spring.datasource.hikari.maximumPoolSize=5

## PostgreSQL

spring.datasource.url=jdbc:postgresql://localhost:5432/example_db4
spring.datasource.username=someuser
spring.datasource.password=123456

spring.jpa.hibernate.ddl-auto=update

http://localhost:8084/执行器/beans/:

"testService": {
"aliases": [],
"scope": "singleton",
"type": "com.test.dbproto4.TestService",
"resource": "file [E:\\Java\\JavaProjects\\dbproto4\\target\\classes\\com\\test\\dbproto4\\TestService.class]",
"dependencies": [
"userRepository"
]
}

"userRepository": {
"aliases": [],
"scope": "singleton",
"type": "com.test.dbproto4.UserRepository",
"resource": null,
"dependencies": [
"(inner bean)#667aba3e",
"(inner bean)#22b3117e",
"(inner bean)#2607b66f",
"jpaMappingContext"
]
}

actuator显示了名为“testservice”的bean,但spring没有看到它。如何从applicationcontext获取bean“testservice”?

uqjltbpv

uqjltbpv1#

解决方案
对dbproto4application类执行这些更改

ApplicationContext javaConfigContext = SpringApplication.run(Dbproto4Application.class, args); 

TestService testServiceObj = (TestService) javaConfigContext.getBean("testService");

问题
在spring引导应用程序中,您已经配置了两个不同的spring应用程序上下文。

// 1st application context and the one which Actuator endpoint is referring to
SpringApplication.run(Dbproto4Application.class, args); 

// 2nd application context which is created here from which you want testService bean
ApplicationContext javaConfigContext = new AnnotationConfigApplicationContext(SpringConfig.class);
TestService testServiceObj = (TestService) javaConfigContext.getBean("testService");

注意,您创建的第二个应用程序上下文是从springconfig构建的,springconfig只能访问com.test.dbproto4.infrastructure.storage.jdbcrepos包中定义的bean。它不能访问testservicebean。

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