我做了一个程序,它应该显示一个方程后,选择了一种代数方程,它不工作的一些原因。我尝试过更改扫描仪名称,但它只是显示错误的选择时,一个表达式被选中。如果你能帮我我会非常感激的谢谢。代码如下:
/**WAP using switch case to print the following :
1. 3X+4Y+Z
2. 3A^2+4B^3+3C*/
import java.util.*;
class F
{
public static void main(String a[])
{
Scanner in = new Scanner(System.in);
System.out.println("Algebra Program executed : No. to be typed: ");
System.out.println(" (i) 3X+4Y+Z 1 ");
System.out.println(" (ii) 3A^2+4B^3+3C 2 ");
int ch = in.nextInt();
switch(ch)
{
//Program 1
case '1': Scanner sc = new Scanner(System.in);
System.out.println("Type a number for X...");
int X = sc.nextInt();
System.out.println("Type a number for Y...");
int Y = sc.nextInt();
System.out.println("Type a number for Z...");
int Z = sc.nextInt();
int sum = (3*X)+(4*Y)+Z;
System.out.println(" ");
System.out.println("Value of X is "+X);
System.out.println("Value of Y is "+Y);
System.out.println("Value of Z is "+Z);
System.out.println("Value of 3X+4Y+Z is "+sum);
break;
//Program 2
case '2': Scanner hi = new Scanner(System.in);
System.out.println("Type a number for A...");
double A = hi.nextDouble();
System.out.println("Type a number for B...");
double B = hi.nextDouble();
System.out.println("Type a number for C...");
double C = hi.nextDouble();
double pro = 3*Math.pow(A, 2) + 4*Math.pow(B, 3) + 3*C;
int isum = (int) pro;
System.out.println(" ");
System.out.println("Value of A is "+A);
System.out.println("Value of B is "+B);
System.out.println("Value of C is "+C);
System.out.println("Value of 3A^2+4B^3+3C is "+isum);
break;
//Else
default: System.out.println("Wrong Choice");
}
}
}```
1条答案
按热度按时间brvekthn1#
你得把案子改成
case 1
以及case 2
而不是case '1'
以及case '2'
.请注意
'1'
以及'2'
是char
文字;不是那个int
文字。的ascii值'1'
是49
那就是'2'
是50
.