使用eclipse,我的项目文件夹hackgsu中有一个名为bad_words.txt的文件。我要定位文件并读取文件的内容。我看到了如何读取文本文件相对路径的答案,我尝试了以下方法:
private static String words[][] = new String[3][];
private static int ok = 17 + 2; //Add two for comment & empty line in text file
private static int med = 26 + 2; //Add two for comment & empty line in text file
private static int bad = 430 + 1; //Add one for comment in text file
private static String p = new File("").getAbsolutePath();
public static String[][] openFile() {
p.concat("/HackGSU/bad_words.txt");
//Set the a limit for the amount of words in each row
words[0] = new String[getOk()];
words[1] = new String[getMed()];
words[2] = new String[getBad()];
//Read the text file to add bad words to an array
try {
FileReader fr = new FileReader(p);
//Wrap file
BufferedReader br = new BufferedReader(fr);
//Add each line of file into the words array
for(int i = 0; i < words.length; i++) {
for(int j = 0; j < words[i].length; j++) {
try {
words[i][j] = br.readLine();
}
catch (IOException e) {
e.printStackTrace();
}
}
}
}
catch (FileNotFoundException e1) {
e1.printStackTrace();
}
return words;
}
但我收到了回溯:
java.io.FileNotFoundException: C:\Users\nbrow_000\workspaceProjects\HackGSU (Access is denied)
at java.io.FileInputStream.open0(Native Method)
at java.io.FileInputStream.open(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileInputStream.<init>(Unknown Source)
at java.io.FileReader.<init>(Unknown Source)
at gsu.hack.harassment.BadWords.openFile(BadWords.java:28)
at gsu.hack.harassment.HarassFilter.<clinit>(HarassFilter.java:10)
at gsu.hack.harassment.CheckPercentage.main(CheckPercentage.java:20)
Exception in thread "main" java.lang.NullPointerException
at gsu.hack.harassment.HarassFilter.checkHarass(HarassFilter.java:23)
at gsu.hack.harassment.CheckPercentage.main(CheckPercentage.java:20)
我也回答了如何使用java?直接从internet读取文本文件,但url构造函数有问题。
如果我把本地文件路径(c://…/bad_words.txt)放进去,它就可以正常工作,但是如何让程序读取文件,这样如果我打包软件,它仍然可以找到正确的文件路径。
3条答案
按热度按时间kb5ga3dv1#
您可能应该使用反斜杠而不是斜杠:
也可以尝试键入双反斜杠:
kmpatx3s2#
从错误的Angular 看,你似乎没有得到完整的路径。而不是
尝试
dgiusagp3#
如果资源已经在类路径中,则不需要使用
File
班级。您可以很容易地从类路径获得它,如:或者直接输入流:
既然你有
static
方法使用:此外,正如我在评论中已经提到的:
不符合
p
但是返回一个新的连接字符串,因为字符串是不可变的。简单使用:p+="/HackGSU/bad_words.txt"
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