我的问题是，如果我有一个字符串-在字符串“#”和“.”中有两种类型的字符，我想计算一下，如果每次我移到右边的3和下面的1，我会落在“#”上多少次。例如，给定的字符串如下所示：

...#.#.......##....#.......#...
.#....#.##.#..#.......#.....##.

# ..#...##.####..###.....#......

..#...##...#...#.#......#...#.#
.##.##.#...#.....#.##..##......
.#...#.#.##.###..#...#...#.....
.#..##..#....##.##....##....##.
..#...##....#..###........##...
.#..#..#.#....#.#...#.#......#.
.##.....#...#..#..#..#...###...
.#...#....#..#...........###...
.....#...........##.#......#...
.....#....##......##..#.#......
-1//stops the checking

应该发生的是以下情况，0表示降落在地面上。x表示它落在#上，也就是每次发生这种情况时计数应该增加1：

...#.#.......##....#.......#...
.#.o..#.##.#..#.......#.....##.

# ..#..0##.####..###.....#......

..#...##.0.#...#.#......#...#.#
.##.##.#...#0....#.##..##......
.#...#.#.##.###0.#...#...#.....
.#..##..#....##.##0...##....##.
..#...##....#..###...o....##...
.#..#..#.#....#.#...#.#.0....#.
.##.....#...#..#..#..#...##X...
.#...#....#..#...........###..0//notice here next round it will exceed
.....#...........##.#......#.....0..#...........##.#......#...//line get doubled as if returning to beginning of the 
.....#....##......##..#.#...........X....##......##..#.#......//same here
-1//to stop

所以在开始的时候，我移动到第三个索引，向下移动1到下一行，我检查这个字符是否是“#”，如果是，count所以在这个例子中-它移动3，所以第一行移动到。。。然后下一行是索引3，在本例中是。所以第三个是。等等。如果它落在#count。这是我的代码，但似乎不起作用-

public static Scanner reader = new Scanner(System.in);

public static void main(String[] args) {
    String a = "";//starts empty
    int cnt = 0, b = 0;//cnt++ if '#', b helps us move 3 to the right each time
    a = reader.nextLine(); //gets the string
    if (b + 3 > a.length() - 1) {//checks that the length when moving 3 doesn't exceed string length
        b = 0;// if it does exceed then go all the way to the left of the string
    }
    b += 3;//move right 3
    a = reader.nextLine(); //get next line from the input
    while (a != "-1") {//until there is -1 (to stop getting input) it continues to check
        char c = a.charAt(b -
                1);//takes whats at place b(-1 is because first index is 0 and not1) and note this is three to the right and after it moves down a row!// is line 23
        if (c == '#' && a != "") {//checks if string isn't empty and if the char equals #
            cnt++;//if yes count++
        }
        if (b + 3 > a.length() - 1) {//explained above
            b = 0;
        }
        b += 3;
        a = reader.nextLine();
    }

    System.out.println(cnt);
}

我得到的错误如下：

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 26
    at java.base/java.lang.StringLatin1.charAt(StringLatin1.java:47)
    at java.base/java.lang.String.charAt(String.java:702)
    at q.qq.main(Advent3.java:23)

我们将不胜感激。如果有什么地方不清楚，甚至不知道如何改进，请告诉我：）在聊天和尝试改进后，感谢代码：

public class Advent3 {
    public static Scanner reader= new Scanner(System.in);
    public static void main(String[] args){
            int b=4,cnt=0,line=1,s;
            String str="";
            char charsign;
            str=reader.nextLine();
            s=str.length();
            str=reader.nextLine();

            while(str!=""||str!="-1") {
                line++;
                s=str.length();
                if(b%str.length()==0) {
                    charsign= str.charAt(10);
                }
                else {
                    charsign= str.charAt(b%str.length()-1);
                }
                if(charsign=='#') {
                    cnt++;
                    System.out.println(cnt);
                }
                b+=3;
                str=reader.nextLine();
            }   
            System.out.println(str);

            System.out.println(cnt);
    }
    }

代码本身的工作，我认为我非常接近，但它没有打印正确的答案！我被困住了，非常感谢你的帮助谢谢！