你可以这样做：

Scanner input = new Scanner(System.in);

System.out.print("First value: ");

int start = Integer.parseInt(input.nextLine());//Gets the first number

System.out.print("Second value: ");

int end = Integer.parseInt(input.nextLine());//Gets the second number

for(int i = start; i <= end; i++){
    if(i%2==0){//When the number is divided by 2, it gives a remainder of 0. Modulus helps us get the remainder.
        System.out.println(i+" is even");
    }else{//Doesn't satisfy the first condition. It must be odd.
        System.out.println(i+" is odd");
    }
}

我们使用扫描仪读取用户输入，然后使用 for 循环和杠杆模量( % ). 模数计算一个数除以某个数后的余数。如果一个数除以2得到0的余数，这意味着它可以被2整除。我们可以建立一个 if 语句来检查它是否可除。
试运行

First value: 1
Second value: 10
1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even

你可以用 Scanner 从用户处获取最小和最大范围值。
一旦有了这些值，就可以使用一个循环，起始值为最小值，结束值为最大值，步长值为 1 . 在循环中，如果数字可以被 2 （即如果数字%2==0），则偶数打印；否则，打印奇数。
查看java教程中的for语句，了解有关循环语句的更多信息。

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.print("1st value: ");
        int min = scanner.nextInt();

        System.out.print("2nd value: ");
        int max = scanner.nextInt();

        for (int i = min; i <= max; i++) {
            System.out.println(i + " is " + (i % 2 == 0 ? "even" : "odd"));
        }
    }
}

示例运行：

1st value: 8
2nd value: 15
8 is even
9 is odd
10 is even
11 is odd
12 is even
13 is odd
14 is even
15 is odd

简短版本：

https://www.youtube.com/watch?v=cakn0xc6ccq
使用 number % 2 == 0 对于偶数。

长版本：

// Create a new Scanner() to scan System.in
Scanner scanner = new Scanner(System.in);

// Get the two inputs
int first = scanner.nextInt();
int second = scanner.nextInt();

// Start i as the first number
// While it is less than or equal to the second
// Add one each time
for(int i = first; i <= second; i++) {

    // Is there a remainder from dividing i by 2?
    // If no, it's even
    boolean even = i % 2 == 0;

    // Print it
    System.out.println(i + " is even: " + even);
}

    scanner.close();

嘿，你可以用for循环，很简单。

for(int i=8;i<=15;i++){
if(i%2==0){
System.out.println(i+"is even");
}else{

System.out.println(i+"is odd");
}
}

我希望你知道如何询问输入，所以把它传递到8和15的位置