问题考虑一次考试有4道试题。一页由一个问题组成，是一个多选题。您可以使用特定命令在问题之间前后移动。每一页都应表示为一个类，最后一页是您在这些问题中选择的内容的摘要。写一个程序，让你用面向对象的方法来实现。
命令-用户可以在程序中使用

start() - To start the test and the first page of the test should be given once this command run.
next_page() - To move to the next page
back_page() - To move back a page
select(int i) - Select an answer on the current page

我被赋予上述问题，我需要写一个程序，工作的意图。这是我到目前为止的情况。我可以自由设计的程序，任何方式，我想没有任何限制。如果我下面的设计是完全错误的，请随时告诉我该如何处理这个问题。
我的问题课是这样的：

class Question1
int answer;
void display(){
    print("This is Question1")
    print("1. Answer")
    print("2. Answer")
    print("3. Answer")
    print("You have selected:" + answer);
}
void select(int i){
  this.answer = i;
}

在其他问题课上。它看起来相似，但问题和选择不同。
在小结课上，它将打印出我选择的内容

class Summary() {
   void display(){
      print("Summary")
      print("In question 1, you've selected: " + Question1.answer);
      print("In question 2, you've selected: " + Question2.answer)
      print("In question 3, you've selected: " + Question3.answer)
      print("In question 4, you've selected: " + Question4.answerr);
    }
}

我有一门应用课程。就像这个程序的大脑。它存储了打印display（）方法的正确类所需的所有信息。它记录了我现在在哪一页。此外，我可以转到下一页，向后移动一页，或选择当前页上的答案。另外，我还有一个抽象的page类，其中每个问题都继承自page类。

//How exactly does the page cluster work?
            +--------+----  Page  -+---------+-----------+(This is an abstract class)
            |        |             |         |           |
     Question1     Question2   Question3 Question4  Summary (This the 5 pages, that inherited from Page class with)

class Application
int current_p; // Current position of the question.
Page p[] = new Page[5];

public Application(){//Constructor
   p[0] = new Quesion1;
   p[1] = new Quesion2;
   p[2] = new Quesion3;
   p[3] = new Quesion4;
   p[4] = new Summary;
   current_p = 1;
}
public start(){
   p[current_p].display();
}
public next(){
  current_p++;
  p[current_p].display();
}
public back(){
  current_pn--;
  p[current_p].display();
}
public select(int i){
   p[cuurent_p].select(i);// Go back to my Question class to see how select work.
   p[current_p].display();
}

因为这是如此之长，它可能会对我试图做什么感到困惑。下面是一个输出示例

Main(){
 Application a = new Application();
 a.start();
 a.select(2);
 a.next();
 a.select(1);
 a.next();
 a.next();
 a.next();
}

在命令行中，它应该输出如下内容：

This is Question1
1. Answer
2. Answer
3. Answer
You have selected: 0

This is Question1
1. Answer
2. Answer
3. Answer
You have selected: 2

This is Question2
1. Answer
2. Answer
3. Answer
You have selected: 0 

This is Question2
1. Answer
2. Answer
3. Answer
You have selected: 1

This is Question3
1. Answer
2. Answer
3. Answer
You have selected: 0

This is Question4
1. Answer
2. Answer
3. Answer
You have selected: 0

Summary
In question 1, you've selected:  2
In question 2, you've selected:  1
In question 3, you've selected:  0
In question 4, you've selected:  0

所以我现在的问题是，我找不到一种方法来从每个问题中得到答案，并在summary类中显示出来。如果我的设计仍然有效，我应该如何改变我的设计？