我正在尝试创建curl get请求的android版本。在终端上运行良好，但在应用程序中失败。
curl请求（url不是真实的）：
curl -d '{"detail": "Y"}' -H "Content-Type:application/json" -X GET -H "Auth-Token:longstringhereforauthtoken" https://api.myendpoint.com/REST/GSLB/zone-to-get-records-from.com/fqdn-of-domain.com/它毫无疑问地给了我所需要的东西。
好吧，现在我想在android中的截击请求中使用该请求，但是，我得到了回报： Unexpected response code 406 for https://api.myendpoint.com/REST/GSLB/zone-to-get-records-from.com/fqdn-of-domain.com/ 我尝试请求的代码如下（将显示预先设置的相关变量）：
private String url;
private String request;
private String searchRequest;
String selected = getIntent().getStringExtra("node");
String token = getIntent().getStringExtra("token");
url = getResources().getString(R.string.api_url);
request = url + "/Session/";
searchRequest = url + "/GSLB/"+selected+"/"+selected+"/";
ProgressDialog searchDialog = new ProgressDialog(MainActivity.this);
searchDialog.setMessage("Getting zone info...");
searchDialog.show();
JSONObject object = new JSONObject();
try {
object.put("Content-Type", "application/json");
object.put("Auth-Token", token);
object.put("detail", "Y");
} catch(JSONException e) {
Log.d(TAG, e.getMessage());
}
Log.d(TAG, "Selected "+icon+", Token: "+token);
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, searchRequest, object,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
searchDialog.dismiss();
Log.d(TAG, String.valueOf(response));
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
searchDialog.dismiss();
if( error instanceof NetworkError) {
Log.d(TAG, error.toString());
Log.d(TAG, "Request to "+searchRequest+" FAILED...");
} else if( error instanceof ServerError) {
Log.d(TAG, "Request to "+searchRequest+" FAILED...");
Log.d(TAG, error.toString());
} else if( error instanceof AuthFailureError) {
Log.d(TAG, error.toString());
Log.d(TAG, "Request to "+searchRequest+" FAILED...");
} else if( error instanceof ParseError) {
Log.d(TAG, error.toString());
Log.d(TAG, "Request to "+searchRequest+" FAILED...");
} else if( error instanceof NoConnectionError) {
Log.d(TAG, error.toString());
Log.d(TAG, "Request to "+searchRequest+" FAILED...");
} else if( error instanceof TimeoutError) {
Log.d(TAG, error.toString());
Log.d(TAG, "Request to "+searchRequest+" FAILED...");
}
}
});
RequestQueue searchRequestQueue = Volley.newRequestQueue(MainActivity.this);
searchRequestQueue.add(jsonObjectRequest);当我收到错误时：
BasicNetwork.performRequest: Unexpected response code 406 for https://api.myendpoint.com/REST/GSLB/zone-to-get-records-from.com/fqdn-of-domain.com/在此活动之前，我有一个loginactivity，它执行类似的请求，这就是get请求中令牌的来源。它发送凭据并接收身份验证令牌。这一个有效，所以我不确定为什么前面的代码段失败了。
登录请求：
JSONObject object = new JSONObject();
try {
object.put("user_name", usernameEditText.getText().toString());
object.put("customer_name", customernameEditText.getText().toString());
object.put("password", passwordEditText.getText().toString());
object.put("Content-Type", "application/json");
} catch(JSONException e) {
Log.d(TAG, e.getMessage());
}
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.POST, request, object,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
if(response != null) {
Log.d("JSON", String.valueOf(response));
String token = null;
pDialog.dismiss();
try {
token = response.getJSONObject("data").getString("token");
Log.d("JSON", token);
} catch (JSONException e) {
Toast.makeText(LoginActivity.this, "" + e.getMessage(),Toast.LENGTH_LONG).show();
e.printStackTrace();
}
Intent loginIntent = new Intent(LoginActivity.this, SelectActivity.class);
loginIntent.putExtra("token", token);
LoginActivity.this.startActivity(loginIntent);
} else {
Toast nullToast = Toast.makeText(LoginActivity.this, "Invalid Credentials\nPlease try again", Toast.LENGTH_LONG);
nullToast.show();
usernameEditText.getText().clear();
customernameEditText.getText().clear();
passwordEditText.getText().clear();
}
}}
我在php和curl中都做过这些请求，但似乎不明白为什么android会失败。我觉得我的语法是正确的，但也许我遗漏了什么？
2条答案
按热度按时间4ioopgfo1#
406 http错误代码保留为“不可接受”。这意味着您的请求的标头不正确。我相信
JsonObjectRequest不管理头，但管理请求主体。为了处理请求头，您需要重写volleyrequest类中的getheaders（）方法，如下所示：qxgroojn2#
线索在请求-响应错误代码（406）中。而不是这样：
我用了
getHeaders()方法发送邮件头，如下所示：虽然我不明白为什么
object.put()不工作（这是在任何教程我看，所以我需要研究更多），这是什么修复它。我现在得到了成功的回应。