如何向用户显示电影列表，让他选择一部电影并将其保存在一个表中

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jsf控制器、服务和dao（2个答案）
5个月前关门了。
我有一个小的网络应用程序，用户应该预订电影。我创建了jsf页面，并通过这种方式显示数据库中可用的电影列表：

<ui:composition template="/template.xhtml">
    <ui:define name="title">
        <h:outputText value="#{bundleMovie.ListMovieTitle}"></h:outputText>
    </ui:define>
    <ui:define name="body">
        <h:form styleClass="jsfcrud_list_form">
            <h:panelGroup id="messagePanel" layout="block">
                <h:messages errorStyle="color: red" infoStyle="color: green" layout="table"/>
            </h:panelGroup>
            <h:outputText escape="false" value="#{bundleMovie.ListMovieEmpty}" rendered="#{movieController.items.rowCount == 0}"/>
            <h:panelGroup rendered="#{movieController.items.rowCount > 0}">
                <h:outputText value="#{movieController.pagination.pageFirstItem + 1}..#{movieController.pagination.pageLastItem + 1}/#{movieController.pagination.itemsCount}"/>&nbsp;
                <h:commandLink action="#{movieController.previous}" value="#{bundleMovie.Previous} #{movieController.pagination.pageSize}" rendered="#{movieController.pagination.hasPreviousPage}"/>&nbsp;
                <h:commandLink action="#{movieController.next}" value="#{bundleMovie.Next} #{movieController.pagination.pageSize}" rendered="#{movieController.pagination.hasNextPage}"/>&nbsp;
                <h:dataTable value="#{movieController.items}" var="item" border="0" cellpadding="2" cellspacing="0" rowClasses="jsfcrud_odd_row,jsfcrud_even_row" rules="all" style="border:solid 1px">
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="#{bundleMovie.ListMovieTitle_movieId}"/>
                        </f:facet>
                        <h:outputText value="#{item.movieId}"/>
                    </h:column>
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="#{bundleMovie.ListMovieTitle_movieName}"/>
                        </f:facet>
                        <h:outputText value="#{item.movieName}"/>
                    </h:column>
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="#{bundleMovie.ListMovieTitle_movieGenre}"/>
                        </f:facet>
                        <h:outputText value="#{item.movieGenre}"/>
                    </h:column>
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="#{bundleMovie.ListMovieTitle_movieRating}"/>
                        </f:facet>
                        <h:outputText value="#{item.movieRating}"/>
                    </h:column>
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="#{bundleMovie.ListMovieTitle_movieDate}"/>
                        </f:facet>
                        <h:outputText value="#{item.movieDate}"/>
                    </h:column>
                    <h:column>
                        <f:facet name="header">
                            <h:outputText value="&nbsp;"/>
                        </f:facet>
                        <h:commandLink action="#{movieController.bookAMovie(movie)}" value="Book" />
                    </h:column>
                </h:dataTable>
            </h:panelGroup>
            <br />
           <h:link outcome="/faces/adminIndex.jsp" value="Return to home page"/>
            <br />
            <br />
        </h:form>
    </ui:define>
</ui:composition>

如你所见，方法 <h:commandLink action="#{movieController.bookAMovie(movie)}" value="Book" /> 应将用户选择保存在新表中，该表为 bookedmovie 同时将表中的数据显示给用户 movie .
方法是：

public int bookAMovie(Movie movie) throws ClassNotFoundException {
    String INSERT_USERS_SQL = "INSERT INTO bookedmovie"
            + "  (bookedmoviename, bookedmoviegenre, bookedmovierating) VALUES "
            + " (?, ?, ?);";

    int result = 0;

    Class.forName("com.mysql.jdbc.Driver");

    try (Connection connection = DriverManager
            .getConnection("jdbc:mysql://localhost:3306/cs230projekat?useSSL=false", "root", "");
            // Step 2:Create a statement using connection object
            PreparedStatement preparedStatement = connection.prepareStatement(INSERT_USERS_SQL)) {

        preparedStatement.setString(1, movie.getMovieName());
        preparedStatement.setString(2, movie.getMovieGenre());
        preparedStatement.setDouble(3, movie.getMovieRating());

        System.out.println(preparedStatement);
        // Step 3: Execute the query or update query
        result = preparedStatement.executeUpdate();

    } catch (SQLException e) {
        // process sql exception
        printSQLException(e);
    }
    return result;
}

我不知道怎么解决这个问题。不一定要这样，如果有人能帮上什么忙，那就适合我了。只向用户显示数据库中的电影，用户可以选择一部电影，并且他的选择存储在一个新表中。

关于java代码，下面的代码运行良好。我能运行它。
只是要确保，您已经在您的项目中添加了适当的mysql库 UserName/Password 应该是正确的。现在您提供了空密码。
因为你没有提供任何错误堆栈。我不能直接对此发表评论。

class Sample3 {
    public static void main(String[] args) throws ClassNotFoundException {
        bookAMovie(Movie.builder().movieGenre("Comic").movieRating(8).movieName("Movie1").build());
    }

    public static int bookAMovie(Movie movie) throws ClassNotFoundException {
        String INSERT_USERS_SQL = "INSERT INTO bookedmovie"
                + "  (bookedmoviename, bookedmoviegenre, bookedmovierating) VALUES "
                + " (?, ?, ?);";

        int result = 0;

        Class.forName("com.mysql.jdbc.Driver");

        try (Connection connection = DriverManager.getConnection("jdbc:mysql://localhost:3306/sample?useSSL=false", "root", "PASSWORD");
             // Step 2:Create a statement using connection object
             PreparedStatement preparedStatement = connection.prepareStatement(INSERT_USERS_SQL)) {

            preparedStatement.setString(1, movie.getMovieName());
            preparedStatement.setString(2, movie.getMovieGenre());
            preparedStatement.setDouble(3, movie.getMovieRating());

            System.out.println(preparedStatement);
            // Step 3: Execute the query or update query
            result = preparedStatement.executeUpdate();

            Statement statement=connection.createStatement();
            ResultSet resultSet=statement.executeQuery("SELECT * FROM sample.bookedmovie");
            List<Map<String, String>> mapList = getList(resultSet);
            System.out.println(mapList);

        } catch (SQLException e) {
            // process sql exception
            e.printStackTrace();
        }
        return result;
    }

    public static List<Map<String, String>> getList(ResultSet resultSet) throws SQLException {
        List<Map<String, String>> mapList = new ArrayList<>();
        ResultSetMetaData resultSetMetaData = resultSet.getMetaData();
        int columnNumber = resultSetMetaData.getColumnCount();
        while (resultSet.next()) {
            Map<String, String> map = new HashMap<>();
            int count = 1;
            while (count <= columnNumber) {
                String columnName = resultSetMetaData.getColumnName(count);
                map.put(columnName, resultSet.getString(columnName));
                count++;
            }
            mapList.add(map);
        }
        return mapList;
    }

}

@Data
@Builder
class Movie {
    public String movieName;
    public String movieGenre;
    public double movieRating;
}

这里我附上了java run的成功截图，mysql中也插入了相同的记录

如何向用户显示电影列表，让他选择一部电影并将其保存在一个表中

1条答案

mysql数据库

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