android studio更改组件可见性时出现空对象引用错误

z6psavjg  于 2021-07-06  发布在  Java
关注(0)|答案(1)|浏览(365)

我正在制作一个应用程序,为不同的用户显示相同的菜单,每个菜单都是一个片段,但根据用户的不同,某些东西是可见的,而其他的则不可见。
但是,当我尝试将组件的可见性设置为 GONE 我得到一个空指针异常错误,我还在测试,所以我只在片段xml上使用textview。
我已经试过初始化两个 TextView 以及 FragmentMenuEncomenda ,我正在使用的片段的类,对象,都在 onCreate() 方法,然后 setContentView() ,就像 tabLayout 以及 viewPager .
if子句只是为了确保用户类型是正确的,所涉及的代码如下:

public class PaginaInicialCliente extends AppCompatActivity {

    private SharedPreferences sharedpreferences;

    private TabLayout tabLayout;
    private ViewPager viewPager;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_pagina_inicial_cliente);

        tabLayout = findViewById(R.id.tabLayoutCliente);
        viewPager = findViewById(R.id.viewPagerCliente);
        ViewPagerAdapter adapter = new ViewPagerAdapter(getSupportFragmentManager());

        //fragments a adicionar
        adapter.addFragment(new FragmentMenuEncomendas(), "Encomendas");
        adapter.addFragment(new FragmentMenuOpcoes(), "Opções");

        //inicializar o tab layout
        viewPager.setAdapter(adapter);
        tabLayout.setupWithViewPager(viewPager);

        sharedpreferences = getSharedPreferences("user", Context.MODE_PRIVATE);

        if (sharedpreferences.getInt("tipo",0)==3) {
            Log.d("USER_DEBUG","Cliente");
            FragmentMenuEncomendas fragmentMenuEncomendas = new FragmentMenuEncomendas();

            //THE ERROR IS HERE
            fragmentMenuEncomendas.getActivity().findViewById(R.id.textViewEncomendas).setVisibility(View.GONE);
        }

    }
}

这个 FragmentMenuEncomenda 班级:

public class FragmentMenuEncomendas extends Fragment {

    View v;

    public FragmentMenuEncomendas(){
    }

    @Nullable
    @Override
    public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        v = inflater.inflate(R.layout.encomendas_fragment, container, false);
        return v;
    }
}

xml文件:

<?xml version="1.0" encoding="utf-8"?>
<androidx.constraintlayout.widget.ConstraintLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <TextView
        android:id="@+id/textViewEncomendas"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="@string/app_name"
        app:layout_constraintBottom_toBottomOf="parent"
        app:layout_constraintEnd_toEndOf="parent"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toTopOf="parent" />

</androidx.constraintlayout.widget.ConstraintLayout>

我搜索的所有答案都不起作用,我不知道这是否是因为我试图更改on create方法内部的可见性。

b4lqfgs4

b4lqfgs41#

因为调用函数时不会创建视图。

public class FragmentMenuEmpresas extends Fragment {

    View v;
    View textView;
    boolean isTextViewShow = false;
    boolean isViewCreated = false;

    public FragmentMenuEmpresas() {
    }

    @Nullable
    @Override
    public View onCreateView(@NonNull LayoutInflater inflater, @Nullable ViewGroup container, @Nullable Bundle savedInstanceState) {
        v = inflater.inflate(R.layout.empresas_fragment, container, false);
        textView = v.findViewById(R.id.textViewEncomendas);
        return v;
    }

    @Override
    public void onViewCreated(@NonNull View view, @Nullable Bundle savedInstanceState) {
        super.onViewCreated(view, savedInstanceState);

        if (isTextViewShow) {

            textView.setVisibility(View.VISIBLE);
        } else {

            textView.setVisibility(View.GONE);
        }

        isViewCreated = true;
    }

    void setIsTextViewShow() {

        if (isViewCreated) {

            textView.setVisibility(View.VISIBLE);
        } else {

            isTextViewShow = true;
        }
    }

    void setIsTextViewGone() {

        if (isViewCreated) {

            textView.setVisibility(View.GONE);
        } else {

            isTextViewShow = false;
        }
    }
}

然后你可以打电话给 setIsTextViewShow 或者 setIsTextViewGone 你想什么时候都行

FragmentMenuEncomendas fragmentMenuEncomendas = new FragmentMenuEncomendas();

 fragmentMenuEncomendas.setIsTextViewShow();//show
 fragmentMenuEncomendas.setIsTextViewGone();//gone

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