jpa:从另一个对象访问一个对象返回null

b0zn9rqh  于 2021-07-08  发布在  Java
关注(0)|答案(0)|浏览(246)

我想,从一个键,访问上面的实体键
这种关系是:
规则包含术语规则。每个termrule包含一个规则和一个变量配置。
只有variableconfiguration包含变量。
我想,从termrule,捕获变量。
我试着这样: termRule.getVariableConfiguration().getVariable() 接收空。
有可能得到一个项的变量吗?

public class Rule extends PersistentObject {

    private static final long serialVersionUID = 7852189080136935020L;

    @Column (name ="NAME", nullable = false)
    private String namerule;

    @OneToMany(mappedBy = "rule", fetch = FetchType.LAZY)
    private List<TermRule> termRule;
}
//getters and setters
public class TermRule extends PersistentObject implements Comparable<TermRule> {
    private static final long serialVersionUID = 336244667983772321L;

    @ManyToOne
    @JoinColumn(name = "ID_RULE", referencedColumnName = "ID", nullable = false)
    private Rule rule;

    @OneToOne 
    @JoinColumn (name ="ID_VAR_CONF", referencedColumnName = "ID", nullable = true)
    private VariableConfiguration variableConfiguration;
}
public abstract class VariableConfiguration extends PersistentObject {

    private static final long serialVersionUID = -4967631633375881594L;

    @ManyToOne
    @JoinColumn(name = "ID_VARIAVEL", referencedColumnName = "ID", nullable = false)
    private Variable variable;

    @OneToOne (mappedBy= "variableConfiguration", cascade = CascadeType.REMOVE, fetch = FetchType.LAZY)
    private TermRule termRule;
}

@DiscriminatorValue("Triangle")
public class Triangle extends VariableConfiguration {
}
public class Variable extends PersistentObject {

    private static final long serialVersionUID = -1172539974105845401L;

    @Column (name = "NOME", nullable = false)
    private String name;

    @OneToMany (mappedBy= "variable", cascade = CascadeType.REMOVE, fetch = FetchType.LAZY)
    private List<VariableConfiguration> variableConfiguration;
}

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