我正在尝试使用递归函数来解析xml文档，我不确定什么样的数据形式（或者我应该说如何保存解析的文档，以什么形式）才能轻松地将其转换为json。这是代码：

private static void printNodeList(NodeList nodeList)
{

    for (int count = 0; count < nodeList.getLength(); count++) //getLength of nodeList that is passed inside of function printNodeList
    {
        Node elemNode = nodeList.item(count); //assign name of element we are currently looking at to a Node "elemNode"
        if (elemNode.getNodeType() == Node.ELEMENT_NODE) //if node we are currently looking at has type ELEMENT_NODE do next block of a code
        {
            // get node name and value
            System.out.println("\nNode Name =" + elemNode.getNodeName()+ " [OPEN]");
            System.out.println("Node Content =" + elemNode.getTextContent());

            if (elemNode.hasAttributes()) //if node we are currently looking at has attributes then do this block of a code
            {
                NamedNodeMap nodeMap = elemNode.getAttributes(); //create nodeMap and pass it attributes of a node we are currently looking at
                for (int i = 0; i < nodeMap.getLength(); i++) //getLength of nodeMap or look how many attributes there is for node that we are currently watching
                {
                    Node node = nodeMap.item(i); //every attribute that is stored in nodeMap will be saved in node and his name and value will be printed out
                    System.out.println("attr name : " + node.getNodeName());
                    System.out.println("attr value : " + node.getNodeValue());
                }
            }
            if (elemNode.hasChildNodes()) //if our element (element that we are currently watching at) still has child nodes left -> recursively call "printNodeList" function
            {
                //recursive call if the node has child nodes
                printNodeList(elemNode.getChildNodes());
            }
            //output in console the name of node that we are done with
            System.out.println("Node Name =" + elemNode.getNodeName()+ " [CLOSE]");
        }
    }
}

代码中使用的xml文件，这是我得到的输出。我不确定我怎么会丢失第一个“node content=…”，因为没有它，它会更干净，可能更容易处理数据？
其思想是解析xml文件，然后保存它，然后使用一组转换规则将保存的文件转换为json。或者有没有一种方法可以直接转换为json而不需要保存解析的xml文件？也许我把xml转换成json的整个方法都错了？救命啊。