当我用json示例运行您的代码时，我得到了一个“jsonexception:jsonobject[“recordone”]is not a string”。。。。。但事实并非如此。用双引号将8括起来：“8”返回您期望的值。如果愿意，可以使用其他get方法getint访问该值。
这个测试用例同时解析一个字符串和一个int。它适合你吗？

package org.nadnavillus.test;

import org.json.JSONObject;
import org.junit.Test;

public class TestCase {

    protected String getTokenValueUnderHeirarchy(String responseString) throws Exception {
        JSONObject json = new JSONObject(responseString);
       String val= json.getJSONObject("data").getJSONObject("paging").getString("RecordOne");
        System.out.println("val::"+val);
        return val;
    }

    protected String getTokenValueUnderHeirarchyInt(String responseString) throws Exception {
        JSONObject json = new JSONObject(responseString);
        int val= json.getJSONObject("data").getJSONObject("paging").getInt("RecordTwo");
        System.out.println("val::"+val);
        return String.valueOf(val);
    }

    @Test
    public void testJson() throws Exception {
        String input = "{\"errors\": [], \"data\": {\"paging\": {\"RecordOne\": \"8\", \"RecordTwo\": 9, \"recordThree\": 2, \"totalNumberOfRecords\": 86052}}}";
        String test = this.getTokenValueUnderHeirarchy(input);
        System.out.println(test);
        test = this.getTokenValueUnderHeirarchyInt(input);
        System.out.println(test);
    }
}