eclipse—在java中，纹理只显示在第一行

bxfogqkk 于 2021-07-09 发布在 Java

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我正在用java做实验，我有一个游戏读取的保存文件，如下所示；

0是一个草纹理（这是工程），但当我改变0的1的改变草变成石头，它不工作过去的第一个，就像我可以改变他们为1，它的作品很好，但不是休息。我坐着试着找这个问题有一段时间了，但找不到。我会更新更多的信息。
处理块类型的代码如下：；

public class Value {
    public static int groundGrass = 0;
    public static int groundRoad = 1;

    public static int airAir = -1;
}

处理文件保存；

import java.io.*;
import java.util.*;

public class Save {
    public void loadSave(File loadPath){
        try{
            Scanner loadScanner = new Scanner(loadPath);

            while(loadScanner.hasNext()){
                for(int y=0;y<Screen.room.block.length;y++){
                    for(int x=0;x<Screen.room.block[0].length;x++){
                        Screen.room.block[y][x].groundID = loadScanner.nextInt();
                    }
                }

                for(int y=0;y<Screen.room.block.length;y++){
                    for(int x=0;x<Screen.room.block[0].length;x++){
                        Screen.room.block[y][x].airID = loadScanner.nextInt();
                    }
                }
            }

            loadScanner.close();
        } catch(Exception e) { }
    }
}

这将处理不同的块类型；

import java.awt.*;

public class Block extends Rectangle{
    public int groundID;
    public int airID;

    public Block(int x, int y, int width, int height, int groundID, int airID){
        setBounds(x, y, width, height);
        this.groundID = groundID;
        this.airID = airID;
    }

    public void draw(Graphics g){
        g.drawImage(Screen.tileset_ground[groundID], x, y, width, height, null);

        if(airID !=Value.airAir){
            g.drawImage(Screen.tileset_ground[airID], x, y, width, height, null);
        }
    }
}

这应该是重要的部分。
我在e.printstacktrace（）中添加了(在正确的地方？）
把这个放在控制台里；

java.lang.NullPointerException
    at com.humans.vs.technology.Save.loadSave(Save.java:14)
    at com.humans.vs.technology.Screen.define(Screen.java:39)
    at com.humans.vs.technology.Screen.paintComponent(Screen.java:47)
    at javax.swing.JComponent.paint(Unknown Source)
    at javax.swing.JComponent.paintChildren(Unknown Source)
    at javax.swing.JComponent.paint(Unknown Source)
    at javax.swing.JComponent.paintChildren(Unknown Source)
    at javax.swing.JComponent.paint(Unknown Source)
    at javax.swing.JLayeredPane.paint(Unknown Source)
    at javax.swing.JComponent.paintChildren(Unknown Source)
    at javax.swing.JComponent.paintToOffscreen(Unknown Source)
    at javax.swing.RepaintManager$PaintManager.paintDoubleBuffered(Unknown Source)
    at javax.swing.RepaintManager$PaintManager.paint(Unknown Source)
    at javax.swing.RepaintManager.paint(Unknown Source)
    at javax.swing.JComponent.paint(Unknown Source)
    at java.awt.GraphicsCallback$PaintCallback.run(Unknown Source)
    at sun.awt.SunGraphicsCallback.runOneComponent(Unknown Source)
    at sun.awt.SunGraphicsCallback.runComponents(Unknown Source)
    at java.awt.Container.paint(Unknown Source)
    at java.awt.Window.paint(Unknown Source)
    at javax.swing.RepaintManager.paintDirtyRegions(Unknown Source)
    at javax.swing.RepaintManager.paintDirtyRegions(Unknown Source)
    at javax.swing.RepaintManager.prePaintDirtyRegions(Unknown Source)
    at javax.swing.RepaintManager.access$700(Unknown Source)
    at javax.swing.RepaintManager$ProcessingRunnable.run(Unknown Source)
    at java.awt.event.InvocationEvent.dispatch(Unknown Source)
    at java.awt.EventQueue.dispatchEventImpl(Unknown Source)
    at java.awt.EventQueue.access$000(Unknown Source)
    at java.awt.EventQueue$3.run(Unknown Source)
    at java.awt.EventQueue$3.run(Unknown Source)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(Unknown Source)
    at java.awt.EventQueue.dispatchEvent(Unknown Source)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(Unknown Source)
    at java.awt.EventDispatchThread.pumpEventsForFilter(Unknown Source)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(Unknown Source)
    at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
    at java.awt.EventDispatchThread.pumpEvents(Unknown Source)
    at java.awt.EventDispatchThread.run(Unknown Source)

完整的代码下载如果有帮助-https://dl.dropbox.com/u/3531994/hvst.zip

Java eclipse

来源：https://stackoverflow.com/questions/12117415/textures-only-show-in-first-line-in-java

1条答案

按热度按时间

ergxz8rk1#

添加 e.printStackTrace 中的异常处理程序 loadSave ，它产生以下输出：

java.lang.NullPointerException
          at com.humans.vs.technology.Save.loadSave(Save.java:14)
          at com.humans.vs.technology.Screen.define(Screen.java:39)
          at com.humans.vs.technology.Screen.paintComponent(Screen.java:47)
          ...

问题是：

Screen.room.block[y][x].groundID = loadScanner.nextInt();

既然我们知道 loadScanner 没有，没有 null 但事实并非如此 null 之前（因为它在上面的几行中就被明确初始化了，并且前8个地面片加载正确），我们认为异常可能是由 Scene.room.block[y][x].groundID .
我们可以排除 Screen.room 以及 Screen.room.block 从成为 null 引用使用与我们用来消除 loadScanner 作为候选人。似乎有些 block[y][x] 是 null . 正在搜索的初始化 Room.block ，我们发现 Room.define ，见下图。

public void define(){
    block = new Block[worldHeight][worldWidth];

    for(int y=0;y<block.length;y++){
        for(int x=0;x<block.length;x++){
            block[y][x] = new Block((Screen.myWidth/2) - ((worldWidth * blockSize)/2) + (x * blockSize), y * blockSize, blockSize, blockSize, Value.groundGrass, Value.airAir);
        }
    }
}

我希望你注意到，你的环覆盖了 x , y 在区间[0， block.length ]; block.length 对应于 worldHeight ，问题就清楚了：这个循环只初始化块的第一个8x8。一旦我们试图读懂 Screen.room.block[y][x].groundID 比如说，块@0，8，我们发现它是默认值， null . 一 NullPointerException 抛出异常处理程序捕获的，而保存文件的其余部分未读。的8x8部分 blocks 已经初始化了 groundID 作为默认值， 0 ，对应于草：

public static int groundGrass = 0;

起初，我怀疑这也会导致房间第一排的前8个街区的未完成渲染，因为 Room.draw 电话 block[y][x].draw(g) 在循环中。。。然而，循环条件在这里也同样被破坏。
现在，解决办法很简单。更正中的循环条件 Room.define 以及 Room.draw ，例如。

for(int y=0;y<worldHeight;y++){
        for(int x=0;x<worldWidth;x++){
            block[y][x] = new Block((Screen.myWidth/2) - ((worldWidth * blockSize)/2) + (x * blockSize), y * blockSize, blockSize, blockSize, Value.groundGrass, Value.airAir);
        }
    }

为了 Room.define ，以及以下 Room.draw .

for(int y=0;y<worldHeight;y++){
        for(int x=0;x<worldWidth;x++){
            block[y][x].draw(g);
        }
    }

您的代码现在生成以下内容：http://puu.sh/yvaj 不客气：-）

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eclipse—在java中，纹理只显示在第一行

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