我正在写一个javarmi程序来计算一个数的阶乘。
这是接口:
import java.rmi.Remote;
import java.rmi.RemoteException;
public interface FactorialRMI extends Remote{
public void setNumber(int val) throws RemoteException;
public int calculateFactorial() throws RemoteException;
}
然后是实现接口的类:
import java.rmi.Naming;
import java.rmi.RemoteException;
import java.rmi.server.UnicastRemoteObject;
public class FactorialRMIImpl extends UnicastRemoteObject implements FactorialRMI{
private int number;
public FactorialRMIImpl(String name) throws RemoteException {
super();
try {
Naming.rebind("myFactorial",this);
}catch(Exception e) {
System.out.println("Exception: "+e.getMessage());
}
}
@Override
public void setNumber(int val) throws RemoteException {
this.number=val;
}
@Override
public int calculateFactorial() throws RemoteException {
int p=1;
for(int i=1;i<=this.number;i++)
p=p*i;
return p;
}
}
以下是服务器代码:
public class FactorialRMIServer {
public static void main(String [] args) {
try {
FactorialRMIImpl myFactorial=new FactorialRMIImpl("myFactorial");
System.out.println("Server is ready...");
}catch(Exception e) {
System.out.println("Exception: "+e.getMessage());
}
}
}
以下是客户代码:
import java.rmi.Naming;
import java.util.*;
public class FactorialRMIClient {
public static void main(String [] args) {
try {
FactorialRMI myFact=(FactorialRMI)Naming.lookup("myFactorial");
Scanner scan=new Scanner(System.in);
System.out.println("Enter a number to calculate its factorial: ");
int n=scan.nextInt();
myFact.setNumber(n);
System.out.println("The factorial of this number is: "+myFact.calculateFactorial());
}catch(Exception e) {
System.out.println("Exception: "+e.getMessage());
}
}
}
我没有使用eclipse。我被要求在jdk的bin文件夹中运行这个程序。我使用的是jdk1.8
要编译java文件,我将这些文件放在bin文件夹中并运行以下命令:
javac *.java
然后我运行命令
rmic FactorialRMIImpl
start rmiregistry
start java FactorialRMIServer
start java FactorialRMIClient
在最后2个命令中,我得到以下错误:
Exception: Connection refused to host: 127.0.0.1; nested exception is:
java.net.ConnectException: Connection refused: connect
命令 start rmiregistry
给我一个错误:
java.rmi.server.ExportException: Port already in use: 1099; nested exception is:
java.net.BindException: Address already in use: NET_Bind
at java.rmi/sun.rmi.transport.tcp.TCPTransport.listen(TCPTransport.java:335)
at java.rmi/sun.rmi.transport.tcp.TCPTransport.exportObject(TCPTransport.java:243)
at java.rmi/sun.rmi.transport.tcp.TCPEndpoint.exportObject(TCPEndpoint.java:411)
at java.rmi/sun.rmi.transport.LiveRef.exportObject(LiveRef.java:147)
at java.rmi/sun.rmi.server.UnicastServerRef.exportObject(UnicastServerRef.java:234)
at java.rmi/sun.rmi.registry.RegistryImpl.setup(RegistryImpl.java:220)
at java.rmi/sun.rmi.registry.RegistryImpl$2.run(RegistryImpl.java:196)
at java.rmi/sun.rmi.registry.RegistryImpl$2.run(RegistryImpl.java:193)
at java.base/java.security.AccessController.doPrivileged(AccessController.java:689)
at java.base/java.security.AccessController.doPrivileged(AccessController.java:873)
at java.rmi/sun.rmi.registry.RegistryImpl.<init>(RegistryImpl.java:193)
at java.rmi/sun.rmi.registry.RegistryImpl$5.run(RegistryImpl.java:531)
at java.rmi/sun.rmi.registry.RegistryImpl$5.run(RegistryImpl.java:529)
at java.base/java.security.AccessController.doPrivileged(AccessController.java:689)
at java.rmi/sun.rmi.registry.RegistryImpl.createRegistry(RegistryImpl.java:528)
at java.rmi/sun.rmi.registry.RegistryImpl.main(RegistryImpl.java:551)
Caused by: java.net.BindException: Address already in use: NET_Bind
at java.base/java.net.PlainSocketImpl.bind0(Native Method)
at java.base/java.net.PlainSocketImpl.socketBind(PlainSocketImpl.java:132)
at java.base/java.net.AbstractPlainSocketImpl.bind(AbstractPlainSocketImpl.java:436)
at java.base/java.net.ServerSocket.bind(ServerSocket.java:386)
at java.base/java.net.ServerSocket.<init>(ServerSocket.java:248)
at java.base/java.net.ServerSocket.<init>(ServerSocket.java:140)
at java.rmi/sun.rmi.transport.tcp.TCPDirectSocketFactory.createServerSocket(TCPDirectSocketFactory.java:45)
at java.rmi/sun.rmi.transport.tcp.TCPEndpoint.newServerSocket(TCPEndpoint.java:666)
at java.rmi/sun.rmi.transport.tcp.TCPTransport.listen(TCPTransport.java:324)
... 15 more
我怎样才能解决这个问题?
1条答案
按热度按时间4si2a6ki1#
如果您在windows上运行,您可以找到在端口上运行的进程,并使用下面的命令终止该进程,以便释放该端口
对于linux