在这段代码中，我需要找到第一个和第二个最小的生成数，我还需要找到总和。到目前为止，除了找到第二小的数字，我什么都做了。如何确保第二小的数字与最小的不同？

String str = JOptionPane.showInputDialog("How many iterations?");
int iter = Integer.parseInt(str);
String str2 = JOptionPane.showInputDialog("What is the max in our range?");
int max = Integer.parseInt(str2);
String str3 = JOptionPane.showInputDialog("What is the minimum in our range?");
int min = Integer.parseInt(str3);
int numcache = max;
int numcache1 = max;

int sum = 0;

for (int a = 0; a <= (iter - 1); a = a + 1) {
    double out;

    out = Math.round(Math.random() * (max - min + 1) + min);
    int output = (int) out;
    System.out.println(output);

    if (output < numcache) {
        numcache = output;
    }

    if (numcache < numcache1) {
        numcache1 = numcache;
    }

    sum = output + sum;

}
System.out.println("The 2nd smallest number is  " + numcache1);
System.out.println("The sum is " + sum);
System.out.println("The smallest number  is " + numcache);

这里是输出，输入20；10; 1

4
    4
    8
    10
    2
    10
    10
    7
    2
    9
    7 
    8
    1
    10
    7
    6
    8
    4
    8
    6
    The 2nd smallest number is  1
    The sum is 131
    The smallest number  is 1