在我的代码中,我可以使用scanner功能提示用户键入一段文本,但是,我只能使其成为用户可以键入一次。要再次键入,我必须关闭终端,然后再次打开它,我如何才能使它,使我可以无限地键入,这样我就不必关闭它,然后每次重新打开它,以便再次键入?上下文,这是我的代码,它是关于一个售票机,它显示某些数据,如人名,价格,总余额等,目前我正在做的地方。这意味着我希望用户键入英格兰的任何城市,并显示一个价格。但正如我所说的,用户一次只能输入一个东西,而他们应该能够不受任何限制地输入。
import java.util.Scanner;
import java.lang.String;
public class TicketMachine
{
private int price;
private int balance;
private int total;
/**
* Create a machine that issues tickets of the given price.
*/
public TicketMachine(int cost)
{
price = cost;
balance = 0;
total = 0;
}
/**
* @Return The price of a ticket.
*/
public int getPrice()
{
return price;
}
/**
* Return The amount of money already inserted for the
* next ticket.
*/
public int getBalance()
{
return balance;
}
/**
* Receive an amount of money from a customer.
* Check that the amount is sensible.
*/
public void insertMoney(int amount)
{
if(amount > 0) {
balance = balance + amount;
}
else {
System.out.println("Use a positive amount rather than: " +
amount);
}
}
/**
* Print a ticket if enough money has been inserted, and
* reduce the current balance by the ticket price. Print
* an error message if more money is required.
*/
public void printTicket()
{
if(balance >= price) {
// Simulate the printing of a ticket.
System.out.println("HERE IS YOUR TICKET");
System.out.println("# Ticket");
System.out.println("# " + price + " cents.");
System.out.println("You have" + balance + "left");
// Update the total collected with the price.
total = total + price;
// Reduce the balance by the price.
balance = balance - price;
}
else {
System.out.println("You must insert at least: " +
(price - balance) + " more cents.");
}
}
/**
* Return the money in the balance.
* The balance is cleared.
*/
public int refundBalance()
{
int amountToRefund;
amountToRefund = balance;
balance = 0;
return amountToRefund;
}
public static void main(String [] args)
{
Scanner myScanner = new Scanner(System.in);
String answer = myScanner.nextLine();
if( answer.equals("London") )
{
System.out.println("£15");
}
if( answer.equals("Manchester") )
{
System.out.println("£20");
}
if( answer.equals("Brighton") )
{
System.out.println("£25");
}
if( answer.equals("Cornwall") )
{
System.out.println("£30");
}
if( answer.equals("Crystal Palace") )
{
System.out.println("£35");
}
if( answer.equals("Chealsea") )
{
System.out.println("£40");
}
if( answer.equals("Birmingham") )
{
System.out.println("£45");
}
if( answer.equals("Liverpool") )
{
System.out.println("£50");
}
if( answer.equals("Bristol") )
{
System.out.println("£55");
}
if( answer.equals("Leister") )
{
System.out.println("£60");
}
if( answer.equals("Newcastle") )
{
System.out.println("£65");
}
if( answer.equals("Cambridge") )
{
System.out.println("£70");
}
if( answer.equals("Bradford") )
{
System.out.println("£75");
}
if( answer.equals("Leeds") )
{
System.out.println("£80");
}
if( answer.equals("Oxford") )
{
System.out.println("£85");
}
if( answer.equals("Nottingham") )
{
System.out.println("£90");
}
if( answer.equals("Peterborough") )
{
System.out.println("£95");
}
if( answer.equals("Sheffield") )
{
System.out.println("£100");
}
}
}
2条答案
按热度按时间j2datikz1#
使用while true或无限循环不是一个好的做法。您可以使用do while并选中标志(例如“exit”)来关闭程序。
ps使用switch case而不是if(){}例如
0mkxixxg2#
将输入和显示部分放入无限循环中,如下所示:
请注意
while (true){...}
创建无限循环块,因为条件已设置为“始终”true
. 有许多其他方法可以创建无限循环。无限循环的另一个例子:然而,第二种形式很少使用,因为它看起来不自然,可能会混淆其他人。