我有一个带有数组的列的Dataframe：

+----------------------------+
|User    | Color             |
+----------------------------+
|User1   | [Green,Blue,Red]  |
|User2   | [Blue,Red]        |
+----------------------------+

我在试着过滤 User1 并将颜色列表放入scala列表：

val colorsList: List[String] = List("Green","Blue","Red")

以下是我迄今为止尝试的内容（输出作为注解添加）：
尝试1：

val dfTest1 = myDataframe.where("User=='User1'").select("Color").rdd.map(r => r(0)).collect()
println(dfTest1)  //[Ljava.lang.Object;@44022255
for(EachColor<- dfTest1){
  println(EachColor)    //WrappedArray(Green, Blue, Red)
}

尝试2：

val dfTest2 = myDataframe.where("User=='User1'").select("Color").collectAsList.get(0).getList(0)
println(dfTest2)  //[Green, Blue, Red]   but type is util.List[Nothing]

尝试3：

val dfTest32 = myDataframe.where("User=='User1'").select("Color").rdd.map(r => r(0)).collect.toList 
println(dfTest32)   //List(WrappedArray(Green, Blue, Red))

for(EachColor <- dfTest32){
  println(EachColor) //WrappedArray(Green, Blue, Red)
}

尝试4：

val dfTest31 = myDataframe.where("User=='User1'").select("Color").map(r => r.getString(0)).collect.toList    
//Exception : scala.collection.mutable.WrappedArray$ofRef cannot be cast to java.lang.String