我一直在用安卓上的凌空,似乎我真的不能让这个特别的部分工作
这是我的json
{
"code": 1,
"status": 200,
"data": "bla... bla..."
}
这是活动课
try
{
JSONObject json_response = new JSONObject(response);
String status = json_response.getString("status");
if (status.equals("200"))
{
do something
}
else
{
Toast.makeText(getApplicationContext(), status, Toast.LENGTH_LONG).show();
}
}
它总是跳过该条件,因为它不匹配,toast打印值200作为状态返回值的证明,并且该值是200
我试过了
int status = json_response.getInt("status");
if (status == 200)
哪个返回“jsonexception:java.lang.string类型的值不能转换为jsonobject”,有什么见解吗?
编辑:
下面是完整的loginactivity.java
package my.sanik.loginandregistration.activity;
import android.app.Activity;
import android.app.ProgressDialog;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.Toast;
import com.android.volley.Request.Method;
import com.android.volley.Response;
import com.android.volley.VolleyError;
import com.android.volley.toolbox.StringRequest;
import org.json.JSONException;
import org.json.JSONObject;
import java.util.HashMap;
import java.util.Map;
import my.sanik.loginandregistration.R;
import my.sanik.loginandregistration.app.AppConfig;
import my.sanik.loginandregistration.app.AppController;
import my.sanik.loginandregistration.helper.SessionManager;
public class LoginActivity extends Activity
{
private static final String TAG = RegisterActivity.class.getSimpleName();
private Button btnLogin;
private Button btnLinkToRegister;
private EditText inputEmail;
private EditText inputPassword;
private ProgressDialog pDialog;
private SessionManager session;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
inputEmail = (EditText) findViewById(R.id.email);
inputPassword = (EditText) findViewById(R.id.password);
btnLogin = (Button) findViewById(R.id.btnLogin);
btnLinkToRegister = (Button) findViewById(R.id.btnLinkToRegisterScreen);
// Progress dialog
pDialog = new ProgressDialog(this);
pDialog.setCancelable(false);
// Session manager
session = new SessionManager(getApplicationContext());
// Check if user is already logged in or not
if (session.isLoggedIn())
{
// User is already logged in. Take him to main activity
Intent intent = new Intent(LoginActivity.this, MainActivity.class);
startActivity(intent);
finish();
}
// Login button Click Event
btnLogin.setOnClickListener(new View.OnClickListener()
{
public void onClick(View view)
{
String email = inputEmail.getText().toString().trim();
String password = inputPassword.getText().toString().trim();
// Check for empty data in the form
if (!email.isEmpty() && !password.isEmpty())
{
// login user
checkLogin(email, password);
}
else
{
// Prompt user to enter credentials
Toast.makeText(getApplicationContext(), "Please enter the credentials!", Toast.LENGTH_LONG).show();
}
}
});
// Link to Register Screen
btnLinkToRegister.setOnClickListener(new View.OnClickListener()
{
public void onClick(View view)
{
Intent i = new Intent(getApplicationContext(), RegisterActivity.class);
startActivity(i);
finish();
}
});
}
private void checkLogin(final String email, final String password)
{
// Tag used to cancel the request
String tag_string_req = "req_login";
pDialog.setMessage("Logging in ...");
showDialog();
StringRequest strReq = new StringRequest(Method.POST, AppConfig.URL_LOGIN, new Response.Listener<String>()
{
@Override
public void onResponse(String response)
{
Log.d(TAG, "Login Response: " + response.toString());
hideDialog();
try
{
JSONObject json_response = new JSONObject(response);
String status = json_response.getString("status");
if (status.equals("200"))
{
session.setLogin(true);
// Launch main activity
Intent intent = new Intent(LoginActivity.this, MainActivity.class);
startActivity(intent);
finish();
}
else
{
// Error in login. Get the error message
Toast.makeText(getApplicationContext(), "Wrong username or password", Toast.LENGTH_LONG).show();
}
}
catch (JSONException e)
{
// JSON error
e.printStackTrace();
Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show();
}
}
}, new Response.ErrorListener()
{
@Override
public void onErrorResponse(VolleyError error)
{
Log.e(TAG, "Login Error: " + error.getMessage());
Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_LONG).show();
hideDialog();
}
}) {
@Override
protected Map<String, String> getParams()
{
// Posting parameters to login url
Map<String, String> params = new HashMap<>();
params.put("email", email);
params.put("password", password);
return params;
}
};
// Adding request to request queue
AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
private void showDialog()
{
if (!pDialog.isShowing()) pDialog.show();
}
private void hideDialog()
{
if (pDialog.isShowing()) pDialog.dismiss();
}
}
5条答案
按热度按时间cpjpxq1n1#
先把你的照片打印出来
response
检查你的回答是什么,或者有没有什么额外的东西。然后和你的价值观比较。
zynd9foi2#
你的
status
不是String
所以,叫这个
然后
注:
你可以用
getInt
直接代替getString
.u4dcyp6a3#
使用此类获取json字符串servicehandler.java
在mainactivty.java中
kjthegm64#
好的,如果问题是字符串或整数抛出异常(我无法在android studio 1.5.1中复制),我建议您这样做:
您也可以先尝试这样做:
希望对你有帮助。
ippsafx75#
试试这个