上下文
在这个问题之后，我为可变收益率创建了三个新列，如下所示。

Regular Contribution    Return/Loss Balance Monthly returns Variable Return/Loss    Variable Return Balance
Date                        
2021-04-30  100 1.250000e+01    1.012500e+03    0.000000    0.000000e+00    1.009000e+05
2021-05-31  100 1.390625e+01    1.126406e+03    0.010016    1.865492e+06    1.511990e+08
2021-06-30  100 1.533008e+01    1.241736e+03    0.013418    2.499015e+06    2.025121e+08
2021-07-31  100 1.677170e+01    1.358508e+03    -0.009173   -1.708369e+06   -1.382708e+08
2021-08-31  100 1.823135e+01    1.476739e+03    -0.013527   -2.519416e+06   -2.039627e+08
... ... ... ... ... ... ...
2104-03-31  100 2.625473e+07    2.126633e+09    0.000164    3.045373e+04    2.567542e+06
2104-04-30  100 2.658292e+07    2.153216e+09    0.002226    4.146561e+05    3.368655e+07
2104-05-31  100 2.691521e+07    2.180132e+09    0.004802    8.942742e+05    7.253388e+07
2104-06-30  100 2.725165e+07    2.207383e+09    -0.000907   -1.688402e+05   -1.357455e+

**可变收益是通过计算一组资产的年收益率除以12得出的，如下代码所示。

但问题是，我无法在for循环中两次使用同一个变量（大写\u insert）：

for date in date_range:
    # fixed return
    current_return_loss = (interest_rate/12) * capital_insert
    return_losses.append(current_return_loss)
    balances.append(capital_insert + current_return_loss)
    capital_insert += (current_return_loss + Additional_contribution)
    fixed_r = capital_insert
    # variable return
    current_var_return_loss = (var_rtns/12) * capital_insert 
    Var_rtn_balance = current_var_return_loss+var_capital_insert
    capital_insert += (current_var_return_loss + Additional_contribution)
    var_capital_insert = capital_insert

这将返回：

pd.concat([fixed_r, var_capital_insert], axis=1)

    0   0
0   8.49966762e+30  8.49966762e+30
1   1.02794206e+32  1.02794206e+32
2   2.39554936e+32  2.39554936e+32
3   8.65418098e+29  8.65418098e+29
4   2.92365668e+29  2.92365668e+29
... ... ...
994 1.82899073e+31  1.82899073e+31
995 8.85282386e+30  8.85282386e+30
996 1.47948140e+31  1.47948140e+31
997 2.80848428e+31  2.80848428e+31
998 6.78230893e+30  6.78230893e+30

我通常只是改变变量名，但我目前正在使用它来构建一个web应用程序，我正在使用这个输入变量来创建图表（在下面的图表中，这是 Initial value .

创建一个新的变量是可能的，并且可以在一个新的数据输入框中使用它，但是我想在走这条路线之前看看是否有办法做到这一点。
问题
是否可以使用相同的变量 capital_insert 在for循环中两次为固定收益率余额和可变收益率余额的最终余额创建列？
可运行示例

# Portfolio

portfolio = pd.DataFrame(columns=['Date', 'Regular Contribution', 'Return/Loss', 'Balance', 'Monthly returns', 'Variable Return/Loss', 'Variable Return Balance'])

interest_rate = 0.15
Additional_contribution = 100   

# start data

today = datetime.date.today()
date_range = pd.date_range(start=today, periods=1000, freq='m') # date

investment = [Additional_contribution]*len(date_range)
return_losses = []
balances = []
var_return_losses = []
var_return_balance = []
capital_insert = 1000
var_capital_insert = 1000
var_rtns = Portfolio.iloc[0:999]

for date in date_range:
    # fixed return
    current_return_loss = (interest_rate/12) * capital_insert
    return_losses.append(current_return_loss)
    balances.append(capital_insert + current_return_loss)
    capital_insert += (current_return_loss + Additional_contribution) # balance for fixed rate of return
    # fixed_r = capital_insert

    # variable return
    current_var_return_loss = (var_rtns/12) * capital_insert 
    Var_rtn_balance = current_var_return_loss+var_capital_insert
    var_capital_insert += (current_var_return_loss + Additional_contribution) # balance for variable rate of return
    # var_capital_insert = capital_insert

portfolio['Date'] = pd.to_datetime(date_range).date
portfolio['Regular Contribution'] = investment
portfolio['Return/Loss'] = return_losses
portfolio['Balance'] = balances
portfolio['Monthly returns'] = var_rtns
portfolio['Variable Return/Loss'] = current_var_return_loss
portfolio['Variable Return Balance'] = Var_rtn_balance

portfolio.set_index('Date', inplace=True)

balance_at_end = balances[-1]
var_balance_at_end = Var_rtn_balance.iloc[-1]