def count_down_skip(start, *args):
    return [num for num in reversed(range(start + 1)) if num not in args]

print("... ".join(map(str, count_down_skip(10,1,4,3))) + "!")

输入的参数不能多于函数定义中的参数。但是，您可以使用*args作为参数。这允许向函数输入可变数量的参数。

您可以选择要跳过的数字列表。然后将每个列表项与 range(num+1) .

def count_down_skip(start, skip = []):
    return [num for num in reversed(range(start + 1)) if num not in skip]

print(count_down_skip(10,[1,4,3]))

# [10, 9, 8, 7, 6, 5, 2, 0]

你可以用 *args ，并检查 num 是成员：

def count_down_skip(start, *skips):
    return [num for num in reversed(range(start+1)) if num not in skips]

print(count_down_skip(10, 1, 4, 3))

输出：

[10, 9, 8, 7, 6, 5, 2, 0]

你的辩论太多了 count_down_skip 功能。如果要输入多个数字，可以使用列表，如下所示：

def count_down_skip(start, skip=0):
    """
    Counting down a sequence with a skip value,
    from a defined start point in reversed order.

    Args:
        start: start loop index.
        skip: number to skip over.

    Returns:
        (list): skipped list.

    """
    return [num for num in reversed(range(start + 1)) if num not in skip]

print("... ".join(map(str, count_down_skip(10, [1,4,3]))) + "!")

最好的解决办法是，

def count_down_skip(start, *skip):
    return [num for num in reversed(range(start + 1)) if num not in skip]

print("... ".join(map(str, count_down_skip(10,1,4,3))) + "!")