我似乎无法添加与相关实体匹配的querybyexample探测。

@Entity
@Data
public class ArtistEntity implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String name;
    private String description;
    @ManyToMany(fetch = FetchType.EAGER)
    private Set<GenreEntity> genreList = new HashSet<>();
    @Version
    private Long version;
}

@Entity
@Data
public class GenreEntity implements Serializable {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String name;
    @Version
    private Long version;
}

@Repository
public interface ArtistRepository extends JpaRepository<ArtistEntity, Long> {
}

当我尝试下面的查询时，根据hibernate的日志，我的探测器没有针对这个类型运行任何条件

GenreEntity genreEntity = new GenreEntity();
genreEntity.setName("Heavy Metal");

ArtistEntity artistEntity = new ArtistEntity();

Set<GenreEntity> genreEntitySet = new HashSet<>();
genreEntitySet.add(genreEntity);

artistEntity.setGenreList(genreEntitySet);

Example<ArtistEntity> example = Example.of(artistEntity);
Pageable pagination = PageRequest.of(0, 10);
artistRepository.findAll(example, pagination);

我还试图查看有关qbe的spring数据jpa文档，但没有发现任何特别提到这个限制的内容，这使我认为这是一个意外的行为。