我已经开始开发一个springbootdatacassandra应用程序。我正在用cassandra在springconfigurationclass中进行配置。当我启动应用程序时，它抛出syntaxerror和cassandraquerysyntaxexception。启动时，为作为帐户实体的表创建cql。它的时间戳字段是“private date createdat”。
通常，时间戳有一个“i”字符，但cql有一个“i”ı" 所以它试着运行一个cql没有ı梅斯坦普”。

Caused by: org.springframework.data.cassandra.CassandraQuerySyntaxException: 
 Query; CQL [CREATE TABLE IF NOT EXISTS accounts (created_at tımestamp, email text, id text,
 is_active boolean, passwd text, uname text, PRIMARY KEY (id));]; 
 line 1:49 no viable alternative at character 'ı'; nested exception is 
 com.datastax.oss.driver.api.core.servererrors.SyntaxError: 
 line 1:49 no viable alternative at character 'ı'

如何解决这个问题并继续？
我的配置类：

@Configuration
@EnableCassandraRepositories
public class CassandraConfiguration extends AbstractCassandraConfiguration {

@Value("${accountservice.cassandra.keyspace.name}")
private String keyspaceName;

@Value("${accountservice.cassandra.port}")
private int port;

@Value("${accountservice.cassandra.contact.point}")
private String contactPoint;

@Value("${accountservice.cassandra.uname}")
private String uname;

@Value("${accountservice.cassandra.passwd}")
private String passwd;

@Override
protected String getKeyspaceName() {
    return keyspaceName;
}

public String getPasswd() {
    return passwd;
}

public String getUname() {
    return uname;
}

@Override
protected String getContactPoints() {
    return contactPoint;
}

@Override
protected int getPort() {
    return port;
}

@Override
public String[] getEntityBasePackages() {
    return new String[] {"com.trius.accountservice"};
}

@Override
public SchemaAction getSchemaAction() {
    return SchemaAction.CREATE_IF_NOT_EXISTS;
}

@Override
public CqlSessionFactoryBean cassandraSession() {
    CqlSessionFactoryBean cqlSessionFactoryBean = super.cassandraSession();
    cqlSessionFactoryBean.setPassword(getPasswd());
    cqlSessionFactoryBean.setUsername(getUname());
    return cqlSessionFactoryBean;
}
}

My Table:

@Data
        @Builder
        @AllArgsConstructor
        @NoArgsConstructor
        @EqualsAndHashCode(of = {"id"})
        @ToString
        @Table(value = "accounts")
        public class Account implements Serializable {
    @PrimaryKey
    private String id = UUID.randomUUID().toString();

    @Column(value="uname")
    private String username;
    @Column(value="email")
    private String email;
    @Column(value="passwd")
    private String passwd;
    @Column(value="is_active")
    private Boolean active;
    @Column(value="created_at")
    private Date createdAt;
     }