如何为 predicate 设置连接

2g32fytz  于 2021-07-23  发布在  Java
关注(0)|答案(1)|浏览(348)

我有一个产品实体:

package com.javaschool.entity;

import lombok.*;

import javax.persistence.*;
import java.util.Set;

@EqualsAndHashCode(of = {"id"})
@ToString(of = { "id", "quantity", "price", "model"})
@Entity
@Table(name = "products")
@Data
@NoArgsConstructor
@AllArgsConstructor
public class Product {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @Column(name = "quantity")
    private int quantity;

    @Column(name = "price")
    private int price;

    @Column(name = "model")
    private String model;

    @Column(name = "is_active")
    private boolean active;

    @Column(name = "picture_url")
    private String url;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name = "category_id")
    private Category category;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name = "brand_id")
    private Brand brand;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name = "season_id")
    private Season season;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name = "color_id")
    private Color color;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name = "material_id")
    private Material material;

    @ManyToOne(fetch = FetchType.EAGER, optional = false)
    @JoinColumn(name = "size_id")
    private Size size;

    @ManyToMany(mappedBy = "productSet", fetch = FetchType.LAZY, cascade = {CascadeType.PERSIST, CascadeType.MERGE})
    private Set<Order> orderSet;
}

我想过滤的类别,季节,颜色,品牌和其他相关参数
目前我的过滤函数是这样的。它适用于模型、价格、数量等参数。也就是说,对于本表中的数据而不是其他数据。如何按从其他表中获取的参数进行筛选?

@Override
    public List<Product> findByParam(List<SearchCriteria> params) {
        CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
        CriteriaQuery<Product> criteriaQuery = criteriaBuilder.createQuery(Product.class);
        Root<Product> root = criteriaQuery.from(Product.class);

        Predicate predicate = criteriaBuilder.conjunction();

        ProductSearchQueryCriteriaConsumer productConsumer = new ProductSearchQueryCriteriaConsumer(predicate, criteriaBuilder, root);

        params.stream().forEach(productConsumer);

        predicate = productConsumer.getPredicate();

        criteriaQuery.where(criteriaBuilder.equal(root.get(Product_.active), true),
                predicate);

        List<Product> result = entityManager.createQuery(criteriaQuery).getResultList();

        return result;
    }

我以为你能打这样的电话,一切都会好起来的。但我错了。

List<SearchCriteria> params = new ArrayList<SearchCriteria>();
        params.add(new SearchCriteria("season_id", ":", "3"));

        List<ProductDto> productDtoList = productService.getProductsByParam(params);
mdfafbf1

mdfafbf11#

我的搜索条件

@Data
@AllArgsConstructor
@NoArgsConstructor
public class SearchCriteria {
    private String key;
    private String operation;
    private Object value;
}

需要这样做:

List<SearchCriteria> params = new ArrayList<SearchCriteria>();
    params.add(new SearchCriteria("category", ":", categoryRepository.findById(1)));

也就是说,在值对象的searchcriteria中,传递一个此类的对象作为筛选依据

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