@带有“order by”(小写)的公式抛出java.lang.stringindexoutofboundsexception

68de4m5k 于 2021-07-24 发布在 Java

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在@formula query string处使用小写的“order by”会引发java.lang.stringindexoutofboundsexception

public class User {
       @Formula("(SELECT string_agg(_a._teamname,';') FROM (SELECT t.name as _teamname FROM team t, teammember tm WHERE tm.team=t.id AND tm.user=id order by t.name) AS _a)")
       proctected String teamNames;
    }

hibernate-core-5.4.20版本

Java spring spring-boot spring-data-jpa Hibernate

来源：https://stackoverflow.com/questions/65979067/formula-with-order-by-lowercase-throws-java-lang-stringindexoutofboundsexce

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按热度按时间

nle07wnf1#

当hibernate计算subselectqueryfragment时，检测到的索引无效：formindex>orderbyindex。解决方法可以使用order by（大写为@formula），并将其作为良好实践扩展到所有sql公式关键字：from、where、，。。。
hibernate-core-5.4.20版本

org.hibernate.engine.spi.SubselectFetch.createSubselectFetchQueryFragment(QueryParameters)

    final int fromIndex = getFromIndex( queryString );
    final int orderByIndex = queryString.lastIndexOf( "order by" );
    final String subselectQueryFragment =  orderByIndex > 0
                ? queryString.substring( fromIndex, orderByIndex )   // -> java.lang.StringIndexOutOfBoundsException 
                : queryString.substring( fromIndex );

hibernate生成querystring

select 
     (...)
     (SELECT string_agg(_a._teamname,';') FROM (SELECT t.name as _teamname FROM team t, teammember tm WHERE tm.team=t.id AND tm.user=:id order by t.name) AS _a) as formula2_2_
     from 
       teammember teammember0_ 
     where (... without order by)

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@带有“order by”(小写)的公式抛出java.lang.stringindexoutofboundsexception

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