postgresql将每个项添加到list-db函数

q5iwbnjs  于 2021-07-24  发布在  Java
关注(0)|答案(1)|浏览(486)

我想创建一个db函数,它将接受一个数字列表并返回一个数字列表。对于传递给函数的列表中的每个项,它应该检查一些条件并将其添加到响应列表中。然而,我不认为我所尝试的方法是正确的。我试着写的基本上是一些伪代码。

CREATE OR REPLACE FUNCTION map_numbers(numbers integer[])
returns integer[]
AS 
$BODY$
   DECLARE return_list integer[];

   FOREACH field IN ARRAY numbers LOOP
      CASE
         WHEN field = 3 THEN -- add 43 (this was a random thought, but I am basically trying to map a few of the numbers to different values)
      END
   END LOOP;

RETURN QUERY SELECT * FROM return_list;
$BODY$
  LANGUAGE sql VOLATILE
  COST 100;
3qpi33ja

3qpi33ja1#

你需要把这个放进一个 IF 声明。要将值附加到数组,请使用 || ```
CREATE OR REPLACE FUNCTION map_numbers(numbers integer[])
returns integer[]
AS
$BODY$
DECLARE
return_list integer[] := integer[];
BEGIN
FOREACH field IN ARRAY numbers LOOP
if field = 3 then
return_list := return_list || 43;
elsif field = 15 then
return_list := return_list || 42;
else
return_list := return_list || field;
end if;
END LOOP;
return return_list; --<< no SELECT required, just return the variable
END;
$BODY$
LANGUAGE plpgsql --<< you need PL/pgSQL, not SQL for the above
STABLE;

也可以使用sql而不是通常更高效的pl/pgsql来实现这一点:

CREATE OR REPLACE FUNCTION map_numbers(numbers integer[])
returns integer[]
AS
$BODY$
select array_agg(field order by idx)
from (
select case
when field = 3 then 43
when field = 15 then 42
else field
end as field,
idx
from unnest(numbers) with ordinality as t(field, idx)
) x;
$BODY$
LANGUAGE sql
STABLE;

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